如何在shell脚本中睡觉？

Question

我尝试在shell脚本中添加sleep命令。但是它显示＆＃34;语法错误：当我运行sh文件时参数＆＃39; 2无效。但是，当我直接发送到提示控制台时，睡眠命令可以正常工作。该 .sh文件脚本如下： '#!/bin/sh sendevent /dev/input/event2 3 57 11 sendevent /dev/input/event2 1 330 1 sendevent /dev/input/event2 1 325 1 sendevent /dev/input/event2 3 53 1343 sendevent /dev/input/event2 3 54 2403 sendevent /dev/input/event2 3 48 3 sendevent /dev/input/event2 0 0 0 sendevent /dev/input/event2 3 53 1341 sendevent /dev/input/event2 3 54 2401 sendevent /dev/input/event2 0 0 0 sendevent /dev/input/event2 3 57 -1 sendevent /dev/input/event2 1 330 0 sendevent /dev/input/event2 1 325 0 sendevent /dev/input/event2 0 0 0 sleep 2 sendevent /dev/input/event2 3 57 12 sendevent /dev/input/event2 1 330 1 sendevent /dev/input/event2 1 325 1 sendevent /dev/input/event2 3 53 1004 sendevent /dev/input/event2 3 54 924 sendevent /dev/input/event2 0 0 0 sendevent /dev/input/event2 3 57 -1 sendevent /dev/input/event2 1 330 0 sendevent /dev/input/event2 1 325 0 sendevent /dev/input/event2 0 0 0

大家可以帮我检查一下吗？

Answer 1

更新谁想知道。答案很简单，只需添加“;”在睡眠命令结束时

sendevent /dev/input/event2 0 0 0 
Sleep;