如果每行都给定值，如何选择行

Question

我有一张表，后面有一行。

现在我正在执行以下查询。

select IdeaId,Count(IdeaId) as Total from testTable 
where IdeaId in (100,2,3) 
group by IdeaId,Status
having Status = 'Submitted'

我给了我结果。

IdeaId  Total
100     1
2       1
3       1

  

但是我想，当我在IN查询中传递Idead ID时，它应该返回   只有那些所有行都有提交状态的IdeadId，如果有的话   对应于IdeaId的行具有除提交之外的状态，然后   那个想法不应该回归。

我正在使用MS SQL server 2014

Answer 1

您似乎希望status - 条款中包含where - 条件，而不是having条款：

select IdeaId,Count(IdeaId) as Total from testTable 
where IdeaId in (100,2,3) AND Status = 'Submitted'
group by IdeaId

修改： 以下查询返回OP 真正想要的内容：IdeaId仅显示的所有行状态＆＃34;已提交＆＃34;而没有别的：

select IdeaId, COUNT(*) Total from testTable WHERE IdeaId in (100,2,3) AND
  IdeaId NOT IN (
    SELECT IdeaId FROM testTable
    WHERE IdeaId in (100,2,3) AND COALESCE(Status,'null') != 'Submitted'
)

在这种情况下，只有IdeaId = 2符合此标准。     IdeaId小组

Answer 2

select IdeaId, count(*) as cnt  
from testTable 
where IdeaId in( 2,3,100)
group by IdeaId 
having count(*) = count(case when Status =  'Submitted' then 1 end)

Answer 3

试试这个，

select IdeaId,Count(IdeaId) as Total from 
( select distinct IdeaId from testTable  
  where Status = 'Submitted' 
  minus 
  select distinct  IdeaId from testTable  
  where Status <> 'Submitted') resultTable
  where IdeaId ( 100,2,3)
  group by IdeaId;

Answer 4

`select IdeaId,
Count(IdeaId) as Total 
from testTable 
where IdeaId in (100,2,3) 
AND Status = 'Submitted' 
and IdeaId not in (select IdeaId from testtable 
                   where Status<> 'Submitted' 
                   or status is  null )
group by IdeaId`    

我想这会给你想要的输出:)

Answer 5

你需要为你的结果使用case语句。

我考虑你使用的是mysql

select IdeaId,Count(IdeaId) as Total
from testTable 
where IdeaId NOT IN(select IdeaId from testTable where Status!='Submitted')
and IdeaId IN(100,2,3)
group by IdeaId,Status