I have a table SITE_SETTINGS like the following:
SITE_ID SETTINGS_CODE UPDATE_TS OTHER_SETTINGS1 OTHER_SETTINGS2
1 CODE1 21-JAN-17 S1 S2
1 CODE1 23-JAN-17 S3 S4
1 CODE2 14-JAN-17 S1 S4
1 CODE2 18-JAN-17 S1 S3
1 CODE2 21-JAN-17 S1 S2
1 CODE3 04-FEB-17 S8 S9
2 CODE1 21-MAR-17 S1 S2
2 CODE2 21-JAN-17 S2 S5
2 CODE1 21-MAR-17 S1 S5
2 CODE2 10-MAR-17 S1 S5
2 CODE3 10-JAN-17 S1 S5
These are multiple SITES, each with 3 different types of SETTINGS_CODE. I need the latest record for each settings_code for all the sites. Something like this:
SITE_ID SETTINGS_CODE UPDATE_TS OTHER_SETTINGS1 OTHER_SETTINGS2
1 CODE1 23-JAN-17 S3 S4
1 CODE2 21-JAN-17 S1 S2
1 CODE3 04-FEB-17 S8 S9
2 CODE1 21-MAR-17 S1 S2
2 CODE2 10-MAR-17 S1 S5
2 CODE3 10-JAN-17 S1 S5
I am trying to do a join on the table with itself but it gives me duplicate records. For example, I get multiple identical records for CODE1 for SITE_ID=1. This is what I have tried:
select t.SITE_ID, t.SETTINGS_CODE, t.OTHER_SETTINGS1, t.OTHER_SETTINGS2, t.UPDATE_TS
from SITE_SETTINGS t
inner join (
select SITE_ID, SETTINGS_CODE, max(UPDATE_TS) as MaxDate
from SITE_SETTINGS
group by SITE_ID, SETTINGS_CODE
order by SITE_ID, SETTINGS_CODE
) tm on t.SITE_ID = tm.SITE_ID and t.SETTINGS_CODE=tm.SETTINGS_CODE and t.UPDATE_TS = tm.MaxDate
I think the issue I am having is inability to group by multiple columns. Is there any way to get data without the duplicates?
答案 0 :(得分:0)
您可以使用row_number()
窗口函数执行此操作:
select * from (
select SITE_SETTINGS.*, row_number() over(partition by SITE_ID, SETTINGS_CODE order by UPDATE_TS desc) as rn
from SITE_SETTINGS
) t
where rn = 1
答案 1 :(得分:0)
SELECT SITE_ID,
SETTINGS_CODE,
LATEST_UPDATE_TS,
OTHER_SETTINGS1,
OTHER_SETTINGS2
FROM
(
SELECT SITE_ID,
SETTINGS_CODE,
UPDATE_TS,
MAX( UPDATE_TS ) OVER ( PARTITION BY SITE_ID,SETTINGS_CODE ORDER BY
UPDATE_TS ) AS LATEST_UPDATE_TS,
OTHER_SETTINGS1,
OTHER_SETTINGS2
FROM SITE_SETTINGS
)
WHERE UPDATE_TS = LATEST_UPDATE_TS;