我仍然是相对较新的PHP，并且对于我正在处理的以下查询，我将非常感谢任何帮助或正确方向上的一点。
我有两个数据库，从中我从每个数据库获取公司的呼叫计数（在特定日期范围内），然后将查询合并到一个表中并显示信息，以及两个计数之间的差异，如下：
ID |名称|日期| FirstDB计数| SecondDB计数|差异|
现在，我有两个主要问题。第一个是第二个数据库表确实包含公司的名称或ID。区分id的唯一方法是在表的名称中。例如，'Dial_Table_1'，公司ID是1，'Dial_Table_2'，id是2，等等。在DB中有一个公司表，它将id与名称相关联，所以我试图运行表名，将它们链接到ID，然后将其插入主查询。到目前为止，这是我的代码：
以下是我的功能：
function getCompanyName($conn, $company_id) {
$sql_companies ="SELECT name AS company, id AS company_id
FROM company
WHERE status = 1
AND id = '$company_id'";
return $sql_companies;
}
function getFirstDBTables($conn) {
$tables = [];
$q = "SELECT DISTINCT job_table
FROM test_type";
$_tables = $conn->query($q);
while ($table = $_tables->fetch_assoc()) {
$tables []= $table["job_table"];
}
return $tables;
}
function getSecondDBTables($conn_seconddb) {
$dial_tables = [];
$r = "SHOW TABLES LIKE 'Dial_Table_%'";
$d_tables = $conn_seconddb->query($r);
while ($d_table = $d_tables->fetch_assoc()) {
$dial_tables []= $d_table["Tables_in_dial_reports (Dial_Table_%)"];
}
return $dial_tables;
}
function constructFirstQuery($conn, $startDate, $endDate, $company_id) {
foreach(getFirstDBTables($conn) as $table) {
$sql []= "SELECT
number.company_id AS company_id,
com.name AS company,
DATE(call_start_time) AS `date`,
COUNT(*) AS `sub_total`,
'$table' AS `table`
FROM $table
LEFT JOIN number ON number.id = $table.number_id
LEFT JOIN company AS com on com.id=number.company_id
WHERE $table.show IS TRUE
AND call_start_time BETWEEN '$startDate 00:00:00' AND '$endDate 23:59:59'
AND $table.processing_complete = 1
GROUP BY `date`, company_id";
}
$sql = implode("\n UNION \n", $sql);
return $sql = "SELECT company, company_id, `date`, SUM(sub_total) AS FirstDB_Count, 0 AS SecondDB_Count FROM ($sql) AS tempTable1 GROUP BY `date`, company_id";
}
function constructSecondQuery($conn_seconddb, $startDate, $endDate, $company_id) {
foreach(getSeconddbTables($conn_seconddb) as $table) {
$company_id = str_replace('Dial_Table_', '', $table);
$sql_dt []= "SELECT
$company_id AS company_id,
DATE(start_time) AS `date`,
COUNT(*) AS sub_total
FROM $table
WHERE $table.published = 1
AND start_time BETWEEN '$startDate 00:00:00' AND '$endDate 23:59:59'
GROUP BY `date`, company_id";
}
}
$sql_dt = implode("\n UNION \n", $sql_dt);
return $sql_cr = "SELECT ' ' AS company, company_id,`date`, 0 AS FirstDB_Count, SUM(sub_total) AS SecondDB_Count FROM ($sql_dt) AS tempTable2 GROUP BY `date`, company_id";
}
这是我的主要代码块（我尝试了很多不同的想法，并对它们进行了评论）：
<?PHP
$sql = "";
$sql_cr = "";
$sql_companies = "";
$name = "";
$sql = constructFirstQuery($conn, $startDate, $endDate, $company_id);
$result_firstdb = $conn->query($sql) or die($conn->error);
$sql_dt = constructSecondQuery($conn_seconddb, $startDate, $endDate, $company_id);
$result_dt = $conn_reportingdb->query($sql_dt) or die($conn_seconddb->error);
/***
* This will save companies ID and names to an array
* And will return an array of the companies
*/
// while ($row = $result_companies->fetch_assoc()) {
// echo $row['company']. ' ';
// }
$total_results = array();
while ($row = $result_firstdb->fetch_assoc()) {
$total_results[$row['company_id']] = $row;
}
while ($row = $result_dt->fetch_assoc()) {
//$company_id = $row['company_id'];
// $sql_companies = getCompanyNames($conn, $company_id);
// $result_companyNames = $conn->query($sql_companies) or die($conn->error);
// while ($row2 = $result_companies->fetch_assoc()){
// $total_results[$row[$company_id]] = $row2['company_id'];
//}
if(!isset($total_results[$row['company_id']])) {
$total_results[$row['company_id']] = $row;
$company_id = $row['company_id'];
$sql_companies = getCompanies($conn, $company_id);
$result_companyNames = $conn->query($sql_companies) or die($conn->error);
while ($row2 = $result_companyNames->fetch_assoc()){
$total_results[$row[$company_id]] = $row2['company'];
//$company_id = $row2['company'];
//if(!isset($total_results[$row['company']])){
// $total_results[$row[$company_id]] = $row2['company'];
//} else {
//$total_results[$row['company_id']['company']] = $row2['company'];
//}
}
} else {
$total_results[$row['company_id']]['SecondDB_Count'] = $row['SecondDB_Count']; //**Merging the databases
}
}
//array_push($company_data, $total_results);
//print_r($company_data);
//print_r($company_data[$row['company_id']]);
// if(!isset($company_data[$row['company_id']])) {
// $company_data[$row['company_id']] = $row;
// //print_r($row);
// } else {
// $company_data[$row['company_id']]['Spearline_total'] = $row['Spearline_total']; //**Merge
// }
// while ($row = $result_cr->fetch_assoc()) {
// if(!isset($company_data[$row['company_id']])) {
// $company_data[$row['company_id']] = $row;
// } else {
// $company_data[$row['company_id']]['Reporting_total'] = $row['Reporting_total']; //**Merge
// }
// }
// }
// }
if ($total_results) {
echo"<TABLE><TR><TH>Company</TH>
<TH>Company ID</TH>
<TH>Date</TH>
<TH>Firstdb Total</TH>
<TH>Seconddb Total</TH>
<TH>Difference</TH></TR>";
foreach($total_results as $row) {
$firstdb_total = $row['FirstDB_total'];
$seconddb_total = $row['SecondDB_total'];
$difference = ($firstdb_total - $seconddb_total);
echo"<TR><TD>". $row["company"]. "</TD>";
echo"<TD>". $row["company_id"]. "</TD>";
echo"<TD>". $row["date"]. "</TD>";
echo"<TD>". $row["FirstDB_total"]. "</TD>";
echo"<TD>". $row["SecondDB_total"]. "</TD>";
echo"<TD>". $difference . "</TD></TR>";
}
echo"</TABLE>";
}
所以第一个主要问题是每个数据库中的名称与ID的匹配。在数据库1中，数据库2中的某些公司没有调用计数，因此该表目前给出了DB1中公司的名称，但如果它们仅包含在DB2中，则不返回该名称到桌子。如果有人碰巧知道如何解决这个问题，我将非常感激。
第二个问题是，在返回的表中，日期会相互覆盖。因此，对于每个公司而言，不是为每个指定的日期获取调用计数，而是每次循环时都会覆盖这些行，并且无论指定了多少天，我只会为每个公司获得一行计数。
非常感谢任何一个问题的帮助。正如我所提到的，我仍在学习这一点，并希望得到一些帮助。感谢