Question

我需要建议

Select * 
From dbo.tblActivityDetails 
WHERE  (minWorked =0) 
   and Pillar = (
               select distinct Pillar 
               from dbo.tblActivityDetails 
               where EmpID=0067
                )

收到错误

“子查询返回的值超过1。当子查询跟随=，！=，＆lt;，＆lt; =，＆gt;，＆gt; =或子查询用作表达式时，不允许这样做。”

如何编写查询以实现上述查询结果？

Answer 1

这里你必须使用前1 ...因为distinct会给出不同的结果

Select * From dbo.tblActivityDetails WHERE  (minWorked =0) and Pillar = 
(select top 1 Pillar from dbo.tblActivityDetails where EmpID=0067)

或使用Pillar（代替'='）期望多个值

Select * From dbo.tblActivityDetails WHERE  (minWorked =0) and Pillar in 
    (select distinct Pillar from dbo.tblActivityDetails where EmpID=0067)

Answer 2

您可以使用IN或EXISTS

Select * From dbo.tblActivityDetails d
WHERE  (d.minWorked =0) and d.Pillar IN 
(select  d1.Pillar from dbo.tblActivityDetails d1 where d1.EmpID=0067)

Select * From dbo.tblActivityDetails d
WHERE  (d.minWorked =0) AND 
        EXISTS (select  1 from dbo.tblActivityDetails d1 
                        where d1.EmpID=0067 AND d.Pillar = d1.Pillar)

Answer 3

;with cte As (select distinct Pillar 
               from dbo.tblActivityDetails 
               where EmpID=0067)
Select * 
From dbo.tblActivityDetails As t
Join cte as c
On c.Pillar = t.pillar
WHERE minWorked = 0

这是我的头脑 - 直接打字，我可能会略微说法，但试着看看：）

Answer 4

您的内部查询可以返回多行，因此您必须使用IN关键字而不是=运算符解决方案

select * From dbo.tblActivityDetails WHERE (minWorked =0) and Pillar in (select distinct Pillar from dbo.tblActivityDetails where EmpID=0067)

Answer 5

为什么要使用子查询...只需转到

＆＃13;

Select * 
From dbo.tblActivityDetails 
WHERE minWorked =0 and EMPID=0067

＆＃13;

或者只是去

＆＃13;

Select * 
From dbo.tblActivityDetails 
WHERE  (minWorked =0) 
   and Pillar in (
               select distinct Pillar 
               from dbo.tblActivityDetails 
               where EmpID=0067
                )

＆＃13;

查询内部的Sql查询与Distinct

5 个答案: