Question

这就是HTML的结构;如果兄弟<div>等于type1，我试图获取<p>的值

<div class="zsg-lg">
  <div class="hdp-fact-ataglance">
     <div class="media-bd">
        <p>
           type1
        <div>
            value
<div class="zsg-lg">
  <div class="hdp-fact-ataglance">
     <div class="media-bd">
        <p>
           type2
        <div>
            value2

这是我目前无法使用的XPath，我对如何构建它感到很困惑。

div[contains(@class, "zsg-lg")]/div[contains(@class, "hdp-fact-ataglance")]/div[contains(@class, "media-bd") and [p == "Type"]]/div/text()

Answer 1

我会建议：

normalize-space(
  //div[contains(@class, "zsg-lg")]
  /div[contains(@class, "hdp-fact-ataglance")]
  /div[
      contains(@class, "media-bd")
    and
      normalize-space(p/text())="type1"
  ]
  /div
  /text()
)

Answer 2

看起来语法有点偏，这很有效：

div[contains(@class, "zsg-lg")]/div[contains(@class, "hdp-fact-ataglance")]/div[contains(@class, 'media-bd') and p = 'type1']/div/text()

XPath返回值的兄弟值多次条件

2 个答案: