func xmppStream(_ sender: XMPPStream!, didReceive message: XMPPMessage!){
print(message)
}
结果类似于以下格式,
<message xmlns="jabber:client" from="pubsub.mynet.com" to="002225743@mynet.com" type="headline">
<event xmlns="http://jabber.org/protocol/pubsub#event">
<items type="headline" node="mynet.global">
<item id="1495526003">
<xml>
<title>My Net</title>
<about>Good for you!</about>
<published>2017-05-23 14:23:23</published>
</xml>
</item>
</items>
</event>
<delay xmlns="urn:xmpp:delay" from="admin@mynet.com/jaxl#5022c770097cfbce285d9564a960f9c7" stamp="2017-05-23T07:53:23Z"/>
</message>
如何在<about>
中获取<xml>
。如果有人有答案和想法,请帮我解决问题。