Question

当我为getdriving方向api制作网址时，我想在两个位置之间画两条路的行车路线

O(D*N*logK)

像这样my gerdirection api url

所以当我用谷歌搜索它时说使用urlencoder当我在我的网址中使用时错误没有被抛出但是我的json是空的这样

 Caused by: java.lang.IllegalArgumentException: Illegal character in query at index 133 but the url gives json

请告诉我哪里出错了

我的代码

error_message   "Invalid request. Missing the 'origin' parameter."
routes  
status  "INVALID_REQUEST"

我的parsejson

public String getMapsApiDirectionsUrl() {
    final LatLng source = new LatLng(dsla, dslo);
    final LatLng path1 = new LatLng(dp1la, dp2lo);
    final LatLng path2=new LatLng(dp2la,dp2lo);
    final LatLng dest = new LatLng(ddla, ddlo);
    String origin = "origin=" + source.latitude + "," + source.longitude;
    String waypoints = "waypoints=optimize:true"+"|"+ path1.latitude + ","+ path1.longitude +"|"+ path2.latitude +","+ path2.longitude ;
    String destination = "destination=" + dest.latitude + "," + dest.longitude;
   String way="",sour="",desty="";
    try {
        way = URLEncoder.encode(waypoints, "UTF-8");
      desty = URLEncoder.encode(destination, "UTF-8");
     sour = URLEncoder.encode(origin, "UTF-8");
    }catch (UnsupportedEncodingException e) {

    }
    String key = "AIzaSyDOidVs6_dHl0cjEJ0-OhMfUY0oNFf1SOE ";
    String params = origin+ "&" + destination+ "&" + waypoints +"&"+key;
    String output = "json";

   // String url1="https://maps.googleapis.com/maps/api/directions/json?origin=Adelaide,SA&destination=Adelaide,SA&waypoints=optimize:true|Barossa+Valley,SA|Clare,SA|Connawarra,SA|McLaren+Vale,SA&key=YOUR_API_KEY";
    String url = "https://maps.googleapis.com/maps/api/directions/"
            +output + "?" +params;
    Log.d("taqg",url);
    return url;
}

告诉我，如果parsejson还有任何错误

Answer 1

我认为您的uri编码存在问题。

对于方向uri，我使用了这段代码。它的工作正常。根据您的需要进行修改..

private String getDirectionsUrl(LatLng origin,LatLng dest){
    // Origin of route
    String str_origin = "origin="+origin.latitude+","+origin.longitude;
    // Destination of route
    String str_dest = "destination="+dest.latitude+","+dest.longitude;
    // Sensor enabled
    String sensor = "sensor=false";
    // Building the parameters to the web service
    String parameters = str_origin+"&"+str_dest+"&"+sensor;
    // Output format
    String output = "json";
    return "https://maps.googleapis.com/maps/api/directions/"+output+"?"+parameters;
}

java.lang.IllegalArgumentException：索引133处的查询中的非法字符：

1 个答案: