Question

差不多3天了，我还是无法解决这个问题。简单的情况，我想搜索人名（姓名）。

示例：

首先我写约翰（结果：John Newman，John Stable，John Carens）
然后我用空格写约翰（结果：没有）
之后我继续John N（结果：John Newman）。我需要保持即使我在搜索中写入空格，也会显示名称。

这是关于if / else的第一部分，我在哪里处理2+个单词的数组。感谢

- (void)searchForText:(NSString*)searchText
{
NSString *searchTextt = [searchText stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];

        NSArray *array = [searchTextt componentsSeparatedByString:@" "];


        NSString *firstName = searchTextt;
        NSString *lastName = searchTextt;
        NSString *firstName2 = searchTextt;
        NSString *lastName2 = searchTextt;

        NSPredicate *predicate = nil;

    if ([array count] > 1) {
        firstName = array[0];
        lastName = array[1];
        firstName2 = array[1];
        lastName2 = array[0];

        predicate = [NSPredicate predicateWithFormat:@"(guestName CONTAINS[cd] %@ AND guestSurname CONTAINS[cd] %@)", firstName, lastName];
        NSPredicate *predicate2 = [NSPredicate predicateWithFormat:@"(guestSurname CONTAINS[cd] %@ AND guestName CONTAINS[cd] %@)", lastName2, firstName2];

        NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:@[predicate, predicate2]];


        self.searchResults = [self.mainarray filteredArrayUsingPredicate:compoundPredicate];

    } else {
        NSPredicate *predicate = [NSPredicate predicateWithFormat:@"guestSurname contains[cd] %@", searchText];
        NSPredicate *predicate2 = [NSPredicate predicateWithFormat:@"guestName contains[cd] %@", searchText];
        NSPredicate *predicate3 = [NSPredicate predicateWithFormat:@"guestCompany contains[cd] %@", searchText];


        NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:@[predicate, predicate2, predicate3]];
        self.searchResults = [self.mainarray filteredArrayUsingPredicate:compoundPredicate];

    }


}

修改

- (void)updateSearchResultsForSearchController:(UISearchController *)searchController
{
    NSString *searchString = searchController.searchBar.text;
    [self searchForText:searchString];
    [_maintable reloadData];
}

Answer 1

我有一个类似

的数组

（{ guestName =约翰; guestSurname = Newman; }，{ guestName =约翰; guestSurname =稳定; }，{ guestName =约翰; guestSurname = Carens; }）

我写功能

- (void)searchForText:(NSString*)searchText 
    {
        searchTextt = [searchText stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
        NSArray *array = [searchTextt componentsSeparatedByString:@" "];
        NSString *firstName = searchTextt;
        NSString *lastName = searchTextt;
        NSPredicate *predicate = nil;

        if ([array count] > 1) {
            firstName = array[0];
            lastName = array[1];
            predicate = [NSPredicate predicateWithFormat:@"(guestName CONTAINS[cd] %@ AND guestSurname CONTAINS[cd] %@) OR (guestName CONTAINS[cd] %@ AND guestSurname CONTAINS[cd] %@)", firstName, lastName, lastName, firstName];

        } else {
            predicate = [NSPredicate predicateWithFormat:@"guestName CONTAINS[cd] %@ OR guestSurnamen CONTAINS[cd] %@", firstName, lastName];

        }
        NSArray *arrResult =  [arr filteredArrayUsingPredicate:predicate];;

    }

- (void)updateSearchResultsForSearchController:(UISearchController 
 *)searchController
{
    NSString *searchString = searchController.searchBar.text;
    [self searchForText:searchString];
    [_maintable reloadData];
}

试试这个。这对我有用我在文本域输入“john”时会得到结果。

使用NSPredicate搜索 - 全名

1 个答案: