Question

我正在尝试计算20 ad 40之间的数字可以被4整除。我的值是打印There are 10 numbers divisible by 4而不是There are 6 numbers divisible by 4

我对编程很新，我不确定这是我的数学是错误的，我的返回值还是我的for循环...为什么我得到10而不是6？

class Divisibility{
    public static void main(String[] args) {
        int start = 20, stop = 40, divisor = 4;
        int count = countDivisible(start, stop, divisor);
        System.out.println("There are " + count + " numbers divisible by " + divisor);
    }

    public static int countDivisible(int start, int stop, int divisor) {
        int numbers = start;
        for (int i = start; i <= stop; i++)
            if ((i % divisor) == 0)
                numbers = i / divisor;
        return numbers;
    }
}

Answer 1

您将返回除分数的结果。

    public static int countDivisible(int start, int stop, int divisor) {
        int numbers = 0;
        for (int i = start; i <= stop; i++){
            if ((i % divisor) == 0){
                numbers++;
            }
        }
        return numbers;
    }

Answer 2

您的结果为numbers = i / divisor，最终为40/4。

我认为这就是你要找的东西：

public static int countDivisible(int start, int stop, int divisor) {
    int numbers = 0;
    for (int i = start; i <= stop; i++)
        if ((i % divisor) == 0)
            numbers++
    return numbers;
}

Answer 3

你应从count开始0并相应增加。

public static int countDivisible(int start, int stop, int divisor) {
        int count = 0;
        for (int i = start; i <= stop; i++)
            if ((i % divisor) == 0)
               count++;
        return count;
}

Answer 4

你的countDivisible是错误的..它必须累积条件满足标准的时间

i％divisor == 0

public static int countDivisible(int start, int stop, int divisor) {
    int sum = 0;
    for (int i = start; i <= stop; i++) {
        if ((i % divisor) == 0) {
            sum++;
            System.out.println(i + " is divisible by 4");
        }
    }
    return sum;
}

Answer 5

是的，我已将numbers初始化为0，并将numbers = i / divisor;替换为numbers++;，现在它可以正常运行，谢谢。

public static int countDivisible(int start, int stop, int divisor) {
    int numbers = 0;
     for (int i = start; i <= stop; i++)
        if ((i % divisor) == 0)

        numbers++;

   return numbers;

}

两个值之间的可分数，我该返回什么？

5 个答案: