Question

我在iOS中有一个字符串变量，我想将其转换为字符数组，然后转换为十六进制字节，如0xD6,0xD6等。

如果Objective-C中有一个我可以用于此

的库，那将会很棒

Answer 1

swift 4

 string to byte:

 let strChar = "A" 
 let data1 = [UInt8](self.strChar.utf8)

Answer 2

可能会在这里回答：

字符串to chars：

NSString *s = @"Some string";
const char *c = [s UTF8String];

chars to hex：

- (NSData *)dataFromHexString {
    const char *chars = [self UTF8String];
    int i = 0, len = self.length;

    NSMutableData *data = [NSMutableData dataWithCapacity:len / 2];
    char byteChars[3] = {'\0','\0','\0'};
    unsigned long wholeByte;

    while (i < len) {
        byteChars[0] = chars[i++];
        byteChars[1] = chars[i++];
        wholeByte = strtoul(byteChars, NULL, 16);
        [data appendBytes:&wholeByte length:1];
    }

    return data;
}

参考：NSString (hex) to bytes

在iOS中将字符串转换为字节数组

2 个答案: