所以我在Android中看到很多教程要做POST请求,但我找到了很多代码,但是没有一个真正有用,这让我很疯狂。
代码看起来不错,但我不知道Android是非常奇怪的。
以下是Android中的帖子请求:
thread = new Thread(new Runnable() {
@Override
public void run() {
try {
String data = URLEncoder.encode("pseudo","UTF-8")+"="+URLEncoder.encode(edit.getText().toString(),"UTF-8");
data += "&"+"score"+"="+URLEncoder.encode(String.valueOf(score),"UTF-8");
URL url = new URL("http://mywebsite/serveur.php?"+data);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setReadTimeout(10000);
connection.setConnectTimeout(15000);
connection.setRequestMethod("POST");
connection.setDoOutput(true);
OutputStream os = connection.getOutputStream();
BufferedWriter wr = new BufferedWriter(new OutputStreamWriter(os,"UTF-8"));
wr.write(data);
wr.flush();
wr.close();
os.close();
android.util.Log.d("my Tag",data);
connection.connect();
android.content.Intent Npage = new android.content.Intent(SubmiturScore.this, ListOscore.class);
startActivity(Npage);
} catch (IOException e) {
e.printStackTrace();
}
PHP中用于在MySQL数据库中存储数据的服务器代码:
<?php
$reponse = array();
$pseudo = urldecode($_POST['pseudo']);
$score = intval(urldecode($_POST['score']));
$mysqli = new MySQLi("myhost","myuser","mypassword","mydb");
$result = $mysqli->query("INSERT INTO SIDB (pseudo,score) VALUES('$pseudo',$score)");
if ($mysqli->connect_error) {
die('Connect Error (' . $mysqli->connect_errno . ') '
. $mysqli->connect_error);
}
if ($result) {
$response["success"] = 1;
$response["message"] = "SUCCESS!";
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "FAILURE!";
echo json_encode($response);
} ?>
我已经在堆栈溢出中发布了一条消息,但我认为代码可以正常工作但是没有......你能帮帮我吗?
答案 0 :(得分:0)
所以我不知道Android上的POST发生了什么。为了解决我的问题,我刚刚调用了一个webview,它将使用数据来收取URL,这样php脚本就可以恢复数据并最终将其存储在数据库中......
这很艰难,但我终于成功了!
wb.getSettings().setJavaScriptEnabled(true);
wb.getSettings().setDomStorageEnabled(true);
wb.loadUrl("http://yourscript.php?"+data);