当我尝试从github接收访问令牌时,这就是问题。
OAuthProblemException{error='unsupported_response_type', description='Invalid response! Response body is not application/json encoded', uri='null', state='null', scope='null', redirectUri='null', responseStatus=0, parameters={}}
我希望尽可能保持一般,所以我不想使用GithubTokenResponse
类。我还有哪些选择可以避免例外?
OAuthClient oAuthClient = new OAuthClient(new URLConnectionClient());
OAuthClientRequest request = OAuthClientRequest
.tokenLocation("https://github.com/login/oauth/access_token")
.setCode(code)
.setGrantType(GrantType.AUTHORIZATION_CODE)
.setClientId(id)
.setClientSecret(secret)
.buildQueryMessage();
OAuthAccessTokenResponse tk = oAuthClient.accessToken(request); //this causes the problem
“丑陋”的解决方案:
GitHubTokenResponse tk = oAuthClient.accessToken(request, GitHubTokenResponse.class);
答案 0 :(得分:2)
它也适用于OAuthJSONAccessTokenResponse。以下是我尝试的代码,它工作正常。
OAuthClient client = new OAuthClient(new URLConnectionClient());
OAuthClientRequest request =
OAuthClientRequest.tokenLocation(TOKEN_REQUEST_URL)
.setGrantType(GrantType.CLIENT_CREDENTIALS)
.setClientId(CLIENT_ID)
.setClientSecret(CLIENT_SECRET)
// .setScope() here if you want to set the token scope
.buildQueryMessage();
request.addHeader("Accept", "application/json");
request.addHeader("Content-Type", "application/json");
request.addHeader("Authorization", base64EncodedBasicAuthentication());
String token = client.accessToken(request, OAuth.HttpMethod.POST, OAuthJSONAccessTokenResponse.class).getAccessToken();
我认为我们需要在标头中设置内容类型。这两行解决了这个问题。
request.addHeader("Accept", "application/json");
request.addHeader("Content-Type", "application/json");
希望得到这个帮助。
答案 1 :(得分:1)
我最后的相同问题由以下修复 -
答案 2 :(得分:0)
在我的情况下,我已经设置了这些标题,但仍然有这个例外。引自1.0.2标签的来源。
try {
this.body = body;
parameters = JSONUtils.parseJSON(body);
} catch (Throwable e) {
throw OAuthProblemException.error(OAuthError.CodeResponse.UNSUPPORTED_RESPONSE_TYPE,
"Invalid response! Response body is not " + OAuth.ContentType.JSON + " encoded");
}
它隐藏了Throwable异常e。在调试时我发现它是org.json.JSONTokener的类找不到错误。所以将org.json jar添加到tomcat lib我可以防止这种异常。