Question

我有一个带有Spinner和EditText的活动。如果我关注EditText，则会显示键盘。好。如果我然后触摸Spinner，键盘应该被隐藏。我得到了这个（见代码）。

现在我的问题：当我关闭Spinner时（无论是否选择了某个项目），如果键盘再次为EditText打开而不点击它，那将会很不错。（当打开Spinner时，焦点仍然在EditText上）

EditText myET = (EditText) findViewById(R.id.editText);
Spinner mySpin = (Spinner) findViewById(R.id.spinner);
InputMethodManager imm = (InputMethodManager) this.getSystemService(Context.INPUT_METHOD_SERVICE);

Spinner.OnTouchListener hideKeyboard = new Spinner.OnTouchListener() {
    @Override
    public boolean onTouch(View v, MotionEvent event) {
        imm.hideSoftInputFromWindow(getCurrentFocus().getWindowToken(), 0);
        return false;
    }
};
mySpin.setOnTouchListener(hideKeyboard);

Answer 1

在onItemSelected

中使用此代码

InputMethodManager imm = (InputMethodManager) 
getSystemService(Context.INPUT_METHOD_SERVICE);
imm.showSoftInput(yourEditText, InputMethodManager.SHOW_IMPLICIT);

这将自动打开下一个editText的键盘。

Answer 2

使用此代码在所选项目上再次显示键盘：

spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
            @Override
            public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
                // open keyboard code here.
            }

            @Override
            public void onNothingSelected(AdapterView<?> adapterView) {

            }
        });

注意：使用点击监听器来满足您的要求。因为spinner上的直接点击监听器不受支持，所以让一个类扩展微调器并在click方法上过度骑行，并且在这个方法中做你想做的事。

/** Spinner extension that calls onItemSelected even when the selection is the same as its previous value */
    public class CutomSpinner extends Spinner {

      public CutomSpinner(Context context)
      { super(context); }

      public CutomSpinner (Context context, AttributeSet attrs)
      { super(context, attrs); }

      public CutomSpinner (Context context, AttributeSet attrs, int defStyle)
      { super(context, attrs, defStyle); }

      @Override public void
      setSelection(int position, boolean animate)
      {
        boolean sameSelected = position == getSelectedItemPosition();
        super.setSelection(position, animate);
        if (sameSelected) {
          // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
          getOnItemSelectedListener().onItemSelected(this, getSelectedView(), position, getSelectedItemId());
        }
      }

      @Override public void
      setSelection(int position)
      {
        boolean sameSelected = position == getSelectedItemPosition();
        super.setSelection(position);
        if (sameSelected) {
          // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
          getOnItemSelectedListener().onItemSelected(this, getSelectedView(), position, getSelectedItemId());
        }
      }
    }

Answer 3

我找到了一个可以执行以下操作的解决方案

当你按下edittext键盘显示然后当你按下微调器时它会消失

然后当你在微调器上选择项目时，即使键盘再次显示相同的项目

最后的概率你有什么，如果我按下微调器（所以键盘消失）然后我按屏幕上的任何地方（我希望键盘重新出现）这很容易只是使全局布尔设置为真每次你使键盘出现和副反之亦然，为活动中的所有视图制作onClickListener，除了spinner ofcourse和onClickListener有以下代码

boolean keyboardIsVisible; // which is true if keyboard is visible
if (!keyboardIsVisible) {
        InputMethodManager imm = (InputMethodManager) 
                getSystemService(Context.INPUT_METHOD_SERVICE);
        imm.showSoftInput(editText, InputMethodManager.SHOW_IMPLICIT);
}

这里的代码解决了除最终问题之外的所有问题，因为我已经告诉过你如何解决它

<强> CustomSpinner.java

public class CustomSpinner extends Spinner {

    Context mainContext;

    public CustomSpinner(Context context) {
        super(context);
        mainContext = context;
    }

    public CustomSpinner (Context context, AttributeSet attrs) {
        super(context, attrs);
        mainContext = context;
    }

    public CustomSpinner (Context context, AttributeSet attrs, int defStyle) {
        super(context, attrs, defStyle);
        mainContext = context;
    }

    @Override public void
    setSelection(int position) {
        boolean sameSelected = position == getSelectedItemPosition();
        super.setSelection(position);
        if (sameSelected) {
            Activity activity = (Activity) mainContext;

            EditText editText = (EditText) activity.findViewById(R.id.edit_text);

            InputMethodManager imm = (InputMethodManager)
                    activity.getSystemService(Context.INPUT_METHOD_SERVICE);
            imm.showSoftInput(editText, InputMethodManager.SHOW_FORCED);
        }
    }
}

<强> MainActivity.java

public class MainActivity extends AppCompatActivity {

    EditText editText;
    Button button;
    CustomSpinner customSpinner;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        editText = (EditText) findViewById(R.id.edit_text);
        button = (Button) findViewById(R.id.button);
        customSpinner = (CustomSpinner) findViewById(R.id.spinner);

        customSpinner.setOnTouchListener(new View.OnTouchListener() {
            @Override
            public boolean onTouch(View view, MotionEvent motionEvent) {
                editText.setEnabled(false);
                editText.setEnabled(true);
                return false;
            }
        });

        customSpinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
            int count = 0;

            @Override
            public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
                if (count > 0){
                    InputMethodManager imm = (InputMethodManager)
                            getSystemService(Context.INPUT_METHOD_SERVICE);
                    imm.showSoftInput(editText, InputMethodManager.SHOW_IMPLICIT);
                }else count++;
            }

            @Override
            public void onNothingSelected(AdapterView<?> adapterView) {
                // Do Nothing
            }
        });
    }

}

Android：隐藏键盘并在微调器关闭后再次显示它

3 个答案: