Question

我有一个特点：

trait A {
    function foo() {
        ...
    }
}

和一个使用这样的特征的类：

class B {
    use A {
        foo as traitFoo;
    }

    function foo() {
        $intermediate = $this->traitFoo();
        ...
    }
}

我想测试课程＆＃39; foo()方法，并希望模拟（使用Mockery）特征的foo()方法的行为。我尝试使用部分和嘲弄traitFoo()之类的：

$mock = Mockery::mock(new B());
$mock->shouldReceive('traitFoo')->andReturn($intermediate);

但它没有用。

有可能这样做吗？还有另一种方法吗？我想测试B::foo()将其与特质的foo()实施隔离开来。

提前致谢。

Answer 1

The proxy mock you are using proxies calls from outside the mock, so internal calls within the class $this->... cannot be mocked.

If you have no final methods, you still can use normal partial mock or a passive partial mock, which extends the mocked class, and don't have such limitations:

$mock = Mockery::mock(B::class)->makePartial();
$mock->shouldReceive('traitFoo')->andReturn($intermediate);
$mock->foo();

UPDATE:

The full example with non-mocked trait functions:

use Mockery as m;

trait A
{
    function foo()
    {
        return 'a';
    }

    function bar()
    {
        return 'd';
    }
}

class B
{
    use A {
        foo as traitFoo;
        bar as traitBar;
    }

    function foo()
    {
        $intermediate = $this->traitFoo();
        return "b$intermediate" . $this->traitBar();
    }
}


class BTest extends \PHPUnit_Framework_TestCase
{

    public function testMe()
    {
        $mock = m::mock(B::class)->makePartial();
        $mock->shouldReceive('traitFoo')->andReturn('c');
        $this->assertEquals('bcd', $mock->foo());
    }
}

用嘲弄嘲弄特质方法

1 个答案: