python：访问“cousin”.txt文件

Question

我有一个像这样的目录结构：

project
  gamelib
    game.py
  levels
    level1.txt

我需要game.py才能访问level1.txt。

with open(path, "r") as f:
  ...

如何访问level1.txt的路径？

Answer 1

要么给它完整的路径

with open("/usr/yourUser/../project/levels/level1.txt", "r") as f:

或相对路径（这认为您的脚本 game.py 位于 ./ project 级别）

with open("./levels/level1.txt", "r") as f:

在您的示例中，您必须返回：

with open("../levels/level1.txt", "r") as f: