长话短说：我编写了一个使用yaml-cpp库来解析YAML文件的模板化函数。此文件包含特定格式的参数列表。该函数返回由参数name参数指定的任意类型的必需参数（因此模板化）。
该功能正常。我使用它来获取main()中的一些参数，如下所示：
int main(int argc, char** argv)
{
const std::string config_file_path = "/home.net/aa17gil/test/test.yaml";
const std::string param_name = "trolley/lasers/laserHoriz/min_rate";
const std::string param_name2 = "software/nodes/slam_karto/max_allowed_load_ratio";
//const std::string param_name3 = "software/nodes/slam_karto/unwanted_topics";
double min_rate;
double ratio;
//const std::string blah = "wtf";
if (getParamFromConfigFile<double>(config_file_path, param_name, min_rate))
std::cout << "min_rate = " << min_rate << std::endl;
else
std::cout << "Could not read param from config file" << std::endl;
if (getParamFromConfigFile<double>(config_file_path, param_name2, ratio))
std::cout << "ratio = " << ratio << std::endl;
else
std::cout << "Could not read param2 from config file" << std::endl;
return EXIT_SUCCESS;
}
一切都很好UNTIL我取消注释第11行const std::string blah = "wtf";中的字符串初始化，或第6行中的字符串初始化。出于某些令人难以置信的原因，执行此操作会导致对{{1}的第二个函数调用返回false。我试过调试这个，但是当我在调试模式下构建项目时它工作正常。 问题仅发生在发布模式。
函数getParamFromConfigFile()如下：
getParamFromConfigFile()如果有帮助，确切的失败点就是检查template <typename T>
bool getParamFromConfigFile(const std::string& config_file_path, const std::string& param_name, T& param_value)
{
YAML::Node node = YAML::LoadFile(config_file_path);
std::vector<std::string> split_name;
boost::split(split_name, param_name, boost::is_any_of("/"));
std::string key_str = split_name.back();
split_name.pop_back();
for(const std::string& str: split_name)
{
if (node.IsNull())
{
std::cout << "Node is null. This happened before dereferencing " << str << std::endl;
return false;
}
node = node[str];
}
if (!node.IsSequence())
{
std::cout << "Final nested map's value is not a sequence" << std::endl;
std::cout << "Is map? " << (node.IsMap() ? "YES" : "NO") << std::endl;
std::cout << "Is scalar? " << (node.IsScalar() ? "YES" : "NO") << std::endl;
std::cout << "Is null? " << (node.IsNull() ? "YES" : "NO") << std::endl;
std::cout << "Is defined? " << (node.IsDefined() ? "YES" : "NO") << std::endl;
return false;
}
for(YAML::Node element: node)
{
if (!element.IsMap())
{
std::cout << "Final entry is not a map!" << std::endl;
return false;
}
if (element.size() != 1)
{
std::cout << "Map has multiple entries" << std::endl;
return false;
}
if (element.begin()->first.Type() != YAML::NodeType::Scalar)
{
std::cout << "Key entry has to be a scalar" << std::endl;
return false;
}
std::string key;
try
{
key = element.begin()->first.as<std::string>();
}
catch (const YAML::TypedBadConversion<std::string>& type_conversion_exception)
{
std::cout << "Error converting param key into string" << std::endl;
std::cout << type_conversion_exception.msg << std::endl;
}
try
{
if (key == key_str)
{
if (element.begin()->second.Type() != YAML::NodeType::Scalar)
{
std::cout << "Key has been found, but the associated value is not a scalar";
return false;
}
param_value = element.begin()->second.as<T>();
return true;
}
}
catch (const YAML::TypedBadConversion<T>& type_conversion_exception)
{
std::cout << "Error covnerting param value into specified data type" << std::endl;
std::cout << type_conversion_exception.msg << std::endl;
}
}
std::cout << "Map key was not found in the file" << std::endl;
return false;
}
。这个条件为真，所以函数返回false。
为什么会发生这种情况？