Question

我最近在Pygame中遇到了这个代码的麻烦，我无法找到我的错误。脚本目前只是一个可控制的精灵，（我理解它并没有显示，因为它被绘制在它上面）但是当我运行我的代码时，它认为小的白色方块（玩家）正在与较大的（，块）碰撞。树）。代码是这样的：

import pygame
from pygame.locals import*

#initialise pygame
pygame.init()

WHITE = (255,255,255)

#counts which sprite you should be on when running


#create screen
screen_width = 160
screen_height = 144
screen_multiplier = 4
screen = pygame.display.set_mode(((screen_width*screen_multiplier), (screen_height*screen_multiplier)))
pygame.display.set_caption('Pokemon Blood Red')

#Sprite stuff
sprite = pygame.image.load('player_east_still.png')
#Reform the sprite
sprite = pygame.transform.scale(sprite, (10*screen_multiplier,   14*screen_multiplier))
sprite.set_colorkey(WHITE)

#############################################################################
class Player(pygame.sprite.Sprite):

    def __init__(self):
        super(Player, self).__init__()
        self.player_sprite = pygame.Surface((10*screen_multiplier, 14*screen_multiplier))
        self.player_sprite.fill(WHITE)
        self.rect = self.player_sprite.get_rect()


class Blocks(pygame.sprite.Sprite):

    def __init__(self):
        super(Blocks, self).__init__()
        self.trees = pygame.Surface((20*screen_multiplier, 40*screen_multiplier))
        self.trees.fill(WHITE)
        self.rect = self.trees.get_rect()

player = Player()
blocks = Blocks()












#############################################################################
#Random variables for later use

amount_caught = 0
place = 1
catch1 = {'pokemon':'none',
          'hp':0,
          'attack':0,
          'defence':0,
          'sp_attack':0,
          'sp_defence':0,}
background = 1
def area_load():
    global background
    if background == 1:
        background = pygame.image.load('neuory_town.png').convert()
        background = pygame.transform.scale(background, (160*screen_multiplier, 144*screen_multiplier))
area_load()
(x) = 160*0.45
(y) = 144*0.45
def caught():
    if amount_caught == 0:
        pass


#Mainloop
crashed = False
while not crashed:
    pressed_keys = pygame.key.get_pressed()
    player.update(pressed_keys)
    x_change = 0
    y_change = 0

    #Different buttons
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            crashed = True
            pygame.quit()
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                x_change = 5*screen_multiplier

              sprite = pygame.image.load('player_west_still.png')
        elif event.key == pygame.K_RIGHT:
            x_change = -5*screen_multiplier

            sprite = pygame.image.load('player_east_still.png')
        elif event.key == pygame.K_UP:
            y_change = -5*screen_multiplier

            sprite = pygame.image.load('player_north_still.png')
        elif event.key == pygame.K_DOWN:
            y_change = 5*screen_multiplier

            sprite = pygame.image.load('player_south_still.png')

    elif event.type == pygame.KEYUP:
        if event.key == pygame.K_LEFT:
            x_change = 0
        elif event.key == pygame.K_RIGHT:
            x_change = 0
        elif event.key == pygame.K_UP:
            y_change = 0
        elif event.key == pygame.K_DOWN:
            y_change = 0    
x += x_change
y += y_change

blockades = pygame.sprite.Group()
blockades.add(blocks)
#Check for collisions
hits = pygame.sprite.spritecollide(player, blockades, True)
if hits:
    print ('Collision!')

#Draw everything
sprite = pygame.transform.scale(sprite, (10*screen_multiplier, 14*screen_multiplier))
sprite.set_colorkey(WHITE)
screen.blit(background,(0,0))
screen.blit(sprite,(x,y))
screen.blit(player.player_sprite, (x, y))
screen.blit(blocks.trees, (200, 200))
pygame.display.flip()
pygame.quit()

感谢您的帮助！

Answer 1

pygame.sprite.spritecollide检查精灵的rect是否重叠。在实例化之后，您永远不会将rects移动到新位置，因此player和blocks仍然位于（0,0）（尝试print(blocks.rect, player.rect)）。要移动它们，您可以更改x和y坐标，topleft，center或rect的other attributes：

blocks.rect.center = (400, 500)
player.rect.topleft = (20, 40)
player.rect.x += 50
player.rect.y += 100

在原始示例中，您不会移动精灵，而只会更改用作图像的blit位置的变量x和y。

# This doesn't change the position of the rect, so there won't be collisions.
x += x_change
y += y_change

您应该移动矩形，然后使用rect作为blit位置：

player.rect.x += x_change
player.rect.y += y_change
screen.blit(player.player_sprite, player.rect)  # Blits the image at rect's topleft coords.

此外，pygame.sprite.Sprite的图片属性应称为image而不是player_sprite。然后你可以将所有精灵放到一个pygame.sprite.Group中，并更新和绘制所有精灵，你只需要两行代码：

# Before the while loop define the sprite group.
all_sprites = pygame.sprite.Group()
# Add all sprites.
all_sprites.add(player)  # And other sprites.

# In the while loop update the sprites.
all_sprites.update()
# And in the draw phase.
all_sprites.draw(screen)

运行脚本时，两个距离很远的对象会识别为碰撞

1 个答案: