在Ruby中查找adj_matrix的最短路径

Question

我是Ruby的新手，我正在尝试在给定adj_matrix（2D数组）的情况下找到从原点节点到目标节点的最短路径。

假设：忽略直接路径可能性

我的代码目前使用以下描述/逻辑。

但是，如果我改为另一个adj_matrix来测试其他测试用例，它将不会返回最佳路径。

还有其他更好的方法吗？

def find_way（adj_matrix，origin，dest）     result = [origin]

destPath = checkDestinationPath(adj_matrix,origin) #[1,2,3,4]
originPath = checkOriginPath(adj_matrix,dest) #[6,7,9]

value = nil
distance = 0
for i in 0..originPath.length-1 
    element = originPath[i] #6,7,9

    path = checkOriginPath(adj_matrix,element) #find which vertex go the element Eg:6-[1,4,7,8,9]  7-[1,6,8]  9-[4,5,6,8]
    allVertexInElement = checkFound(destPath,path) #stores common vertex that are also in destPath (Eg: 4)

    if allVertexInElement.length != 0 
        for j in 0..allVertexInElement.length-1
            currVertex = allVertexInElement[j] #4
            a = checkDestinationPath(adj_matrix,currVertex) 
            distance = adj_matrix[origin][currVertex] #8
            if currVertex == dest  #exit entire for loop
                distance = adj_matrix[origin][currVertex] + adj_matrix[currVertex][dest] 
                value = "#{currVertex}"  + "," + "#{element}" 
                break
            else 
             commonVertex = checkFound2(originPath,a)  # 6,9    
                for k in 0..commonVertex.length-1  #2 or more possible path: 0-4-6-8 vs 0-4-9-8
                    current = commonVertex[k] #6,9
                    distance += adj_matrix[currVertex][current]
                    distance += adj_matrix[current][dest] 

                    if k == 0
                        shortestDist = distance #20
                         value = "#{currVertex}"  + "," + "#{element}"  # 4,6                            
                    else
                        if distance < shortestDist
                            shortestDist = distance #16  
                            value = "#{currVertex}"  + "," + "#{element}"  #4,9

                        end
                    end
                    distance = adj_matrix[origin][currVertex] #reset: 8
                end         
            end   
        end
    end
end

values = value.split(",")
values.each do |x|
    result << x.to_i #4,9
 end

result << dest #8
return result #[0,4,9,8]

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