Question

我是Quartz的新手，我刚刚开始使用已经使用quartz调度程序的项目。项目正在编译，但在运行时会抛出以下异常：

BeanCreationException: Error creating bean with name 'galleryBulkTrigger' defined in ServletContext resource [/WEB-INF/spring/applicationContext-scheduler.xml]: Cannot resolve reference to bean 'galleryBulkJob' while setting bean property 'jobDetail'; nested exception is


org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'galleryBulkJob' defined in ServletContext resource [/WEB-INF/spring/applicationContext-scheduler.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type 'java.lang.String' to required 
type 'java.lang.Class' for property 'jobClass'; nested exception is java.lang.IllegalArgumentException: Cannot find class [com.sgss.nove.quartz.gallery.GalleryBulkJob]:

applicationcontext定义bean如下：

<bean id="galleryBulkTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
    <property name="jobDetail" ref="galleryBulkJob"/>
    <property name="cronExpression" value="#{noveExternalProperties['cronExpression.galleryBulk']}"/>
</bean>

<bean id="galleryBulkJob" class="org.springframework.scheduling.quartz.JobDetailBean">
    <property name="jobClass" value="com.sgss.nove.quartz.gallery.GalleryBulkJob"/>
    <property name="jobDataAsMap">
        <map>
            <entry key="galleryBulkTask" value-ref="galleryBulkTask"/>
        </map>
    </property>
</bean>

，班级GalleryBulkJob如下：

import org.quartz.JobExecutionContext;
import org.quartz.JobExecutionException;
import org.springframework.scheduling.quartz.QuartzJobBean;

public class GalleryBulkJob extends QuartzJobBean {

    private GalleryBulkTask galleryBulkTask;

    public void setGalleryBulkTask(GalleryBulkTask galleryBulkTask) {
        this.galleryBulkTask = galleryBulkTask;
    }

    @Override
    protected void executeInternal(JobExecutionContext jobExecutionContext) throws JobExecutionException {
        galleryBulkTask.executeTask();
    }
}

只要我知道它应该有用，唯一的疑问就是行：<property name="jobClass" value="com.sgss.nove.quartz.gallery.GalleryBulkJob"/>，其中值被视为一个字符串，但是期望一个Class。

如何解决此问题？

提前致谢。

Answer 1

将字符串传递给Spring上下文中的类参数是可以的。
看一下错误信息：找不到类[com.sgss.nove.quartz.gallery.GalleryBulkJob]。
由于某种原因，类似乎不存在于类路径中。

嵌套异常是org.springframework.beans.TypeMismatchException：

1 个答案: