Question

我正在使用Firebase的FriendlyChat codelab中的代码在我的网络应用中实现聊天功能。我想发送推送通知，Firebase解释这是可能的。但是，我不断得到“firebase.messaging不是一个功能”，我完全迷失了它的含义。

有没有人碰到这个？有没有人找到解决方案？

我的html脚本初始化firebase：

// Saves the messaging device token to the datastore.
FriendlyChat.prototype.saveMessagingDeviceToken = function() {
  firebase.messaging().getToken().then(function(currentToken) {
    if (currentToken) {
      console.log('Got FCM device token:', currentToken);
      // Saving the Device Token to the datastore.
      firebase.database().ref('/fcmTokens').child(currentToken)
          .set(firebase.auth().currentUser.uid);
    } else {
      // Need to request permissions to show notifications.
      this.requestNotificationsPermissions();
    }
  }.bind(this)).catch(function(error){
    console.error('Unable to get messaging token.', error);
  });
};

// Requests permissions to show notifications.
FriendlyChat.prototype.requestNotificationsPermissions = function() {
  console.log('Requesting notifications permission...');
  firebase.messaging().requestPermission().then(function() {
    // Notification permission granted.
    this.saveMessagingDeviceToken();
  }.bind(this)).catch(function(error) {
    console.error('Unable to get permission to notify.', error);
  });
};

Messenger.js：

import pandas as pd

groups = pd.DataFrame({'Name': [['Matt','Adam','John','James'], ['Sam','Andrew','John', 'Boss']], 'Job': ['Peon', 'Owner'], 'Group': ['Boss', 'Leader']})

# Build a list of tuples with row to draw group and job from and name
x = [(idx, i) for idx, j in enumerate(groups['Name']) for i in j]

# Search the list for group names, if found resolve group 
# names to additional members of row where group was found
for i, j in x:
    if j in set(groups.Group):
            x.remove((i, j))
            for n in list(*list(groups['Name'][groups.Group == j])):
                x.append((i, n))

# Create new DataFrame
idx, names = zip(*x)
z = pd.DataFrame(list(names), index=list(idx))

# Join on the old one
groups = groups.drop('Name', axis=1).join(z)

firebase.messaging不是一个函数

0 个答案: