我正在做这个请求:
$uid = db_query("SELECT uid FROM tablename WHERE mail = 'test@test.com' LIMIT 1")
得到结果:
资源ID#310
但我想得到这个uid。错误在哪里?
答案 0 :(得分:0)
db_query("SELECT uid FROM tablename WHERE mail = 'test@test.com' LIMIT 1");
只是给你一个“答案”,但你想要它的价值。试试这个:
$result = db_query("SELECT uid FROM tablename WHERE mail = 'test@test.com' LIMIT 1");
$row = db_fetch_array($result);
$uid = $row[0];