Question

我希望这段代码能够获得15倍的数据量。当它运行时，它第一次进入所有的for循环，然后打印出答案，但是当它在第二次循环时在＆＃34;对于num in范围（0,15）：＆＃ 34;循环，它进入＆＃34;对于页面中的df：＆＃34;然后不再深入到其他循环中，只返回＆＃34; page_counter＆＃34;按原样递增200。

每次＆＃34; for num in range（0,15）时，我该怎么做才能让它运行最终的嵌套for循环：＆＃34;循环？

 import pandas as pd

 symbol = 0
 for num in range(symbol,1):
     page_counter =0
     right = 1
     down = 0
     for num in range(0,15):
         page = pd.read_html('https://www.google.com/finance/historical?q=a&startdate=Jan+1%2C+2005&enddate=Mar+2%2C+2017&num=200&ei=Aom4WPizNcWO2AaSnZ3YBg'+ str(page_counter), attrs = {'class': 'gf-table'}, header=0)

         for df in page:
             for num in range(down,200):
                 open_data = df.at[down, 'Open']
                 high_data = df.at[down, 'High']
                 low_data = df.at[down, 'Low']
                 close_data = df.at[down, 'Close']
                 #volume_data = df.at[down, 'Volume']

                 print(open_data)

                 down += 1
         page_counter += 200
         print(page_counter)
      symbol += 1

P.S。我知道我的代码现在有点笨拙，这只是我的一个简单的想法。

Answer 1

在for num in range(0,15):

中声明down = 0

在第一次运行后= 200，因此此循环不满足for num in range(down,200):范围条件。

 import pandas as pd

 symbol = 0
 for num in range(symbol,1):
     page_counter =0
     right = 1
     for num in range(0,15):
         down = 0
         page = pd.read_html('https://www.google.com/finance/historical?q=a&startdate=Jan+1%2C+2005&enddate=Mar+2%2C+2017&num=200&ei=Aom4WPizNcWO2AaSnZ3YBg'+ str(page_counter), attrs = {'class': 'gf-table'}, header=0)

         for df in page:
             for num in range(down,200):
                 open_data = df.at[down, 'Open']
                 high_data = df.at[down, 'High']
                 low_data = df.at[down, 'Low']
                 close_data = df.at[down, 'Close']
                 #volume_data = df.at[down, 'Volume']

                 print(open_data)

                 down += 1
         page_counter += 200
         print(page_counter)
      symbol += 1

Python嵌套for循环只运行一次，然后跳过其余的迭代

1 个答案: