Question

以下面的XML为例，我尝试获取所有<d:LayerXml>标记的内容并将其添加到数组中。使用ElementTree解析XML。

我首先使用名称来访问XML元素，但这很失败，因为显然没有名为＆＃39; entry＆＃39; -

root = ET.fromstring(r.text)
for child in root:
    if child.tag == entry':
        print child.attirb

在我打印出所有子标签（print child.tag）后，我注意到每个标签都以roor元素中提供的xmlns为后缀。例如，＆＃39;条目＆＃39;实际上是＆＃39; {http://www.w3.org/2005/Atom}＆＃39;。

接下来我尝试使用该后缀访问元素，但它只是因语法错误而失败。

root = ET.fromstring(r.text)
for child in root:
    if child.tag == '{http://www.w3.org/2005/Atom}entry':
        layerXML = child.{http://www.w3.org/2005/Atom}content
# Also tried - layerXML = child.'{http://www.w3.org/2005/Atom}content'
        print layerXML

因此，给定以下XML示例，我如何将所有<d:LayerXml>元素的内容添加到数组中。为了澄清，在这种情况下，数组将包含I want this和I want this, too。

<?xml version="1.0" encoding="utf-8"?>
<feed xml:base="https://tablestore.somewhere.com/" xmlns="http://www.w3.org/2005/Atom" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices" xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns:georss="http://www.georss.org/georss" xmlns:gml="http://www.opengis.net/gml">
    <id>https://tablestore.somewhere.com/TableName</id>
    <title type="text">TableName</title>
    <updated>2017-03-02T12:01:04Z</updated>
    <link rel="self" title="TableName" href="TableName" />
    <entry m:etag="W/&quot;datetime'2017-03-02T11%3A46%3A37.1271167Z'&quot;">
        <id>https://tablestore.somewhere.com/TableName(PartitionKey='PartitonKey',RowKey='layer1-tileMatrixSet')</id>
        <category term="tablestore.TableName" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" />
        <link rel="edit" title="TableName" href="TableName(PartitionKey='PartitonKey',RowKey='layer1-tileMatrixSet')" />
        <title />
        <updated>2017-03-02T12:01:04Z</updated>
        <author>
            <name />
        </author>
        <content type="application/xml">
            <m:properties>
                <d:PartitionKey>PartitonKey</d:PartitionKey>
                <d:RowKey>RowKey</d:RowKey>
                <d:Timestamp m:type="Edm.DateTime">2017-03-02T11:46:37.1271167Z</d:Timestamp>
                <d:AuthType>basic</d:AuthType>
                <d:Credentials>CREDENTIALS1</d:Credentials>
                <d:Layer>layer1</d:Layer>
                <d:LayerXml>I want this</d:LayerXml>
                <d:Service>https://www.google.co.uk</d:Service>
                <d:TileMatrixSet>tileMatrixSet</d:TileMatrixSet>
            </m:properties>
        </content>
    </entry>
    <entry m:etag="W/&quot;datetime'2017-03-02T11%3A46%3A37.1271167Z'&quot;">
        <id>https://tablestore.somewhere.com/TableName(PartitionKey='PartitonKey',RowKey='layer2-tileMatrixSet')</id>
        <category term="tablestore.TableName" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" />
        <link rel="edit" title="TableName" href="TableName(PartitionKey='PartitonKey',RowKey='layer2-tileMatrixSet')" />
        <title />
        <updated>2017-03-02T12:01:04Z</updated>
        <author>
            <name />
        </author>
        <content type="application/xml">
            <m:properties>
                <d:PartitionKey>PartitonKey</d:PartitionKey>
                <d:RowKey>RowKey</d:RowKey>
                <d:Timestamp m:type="Edm.DateTime">2017-03-02T11:46:37.1271167Z</d:Timestamp>
                <d:AuthType>basic</d:AuthType>
                <d:Credentials>CREDENTIALS1</d:Credentials>
                <d:Layer>layer2</d:Layer>
                <d:LayerXml>I want this, too</d:LayerXml>
                <d:Service>https://www.google.co.uk</d:Service>
                <d:TileMatrixSet>tileMatrixSet</d:TileMatrixSet>
            </m:properties>
        </content>
    </entry>
</feed>

Answer 1

您还没有说出您遇到的语法错误，以下为我提供了想要的结果：

from xml.etree import ElementTree as ET
xml = '''<?xml version="1.0" encoding="utf-8"?>
<feed xml:base="https://tablestore.somewhere.com/" xmlns="http://www.w3.org/2005/Atom" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices" xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns:georss="http://www.georss.org/georss" xmlns:gml="http://www.opengis.net/gml">
    <id>https://tablestore.somewhere.com/TableName</id>
    <title type="text">TableName</title>
    <updated>2017-03-02T12:01:04Z</updated>
    <link rel="self" title="TableName" href="TableName" />
    <entry m:etag="W/&quot;datetime'2017-03-02T11%3A46%3A37.1271167Z'&quot;">
        <id>https://tablestore.somewhere.com/TableName(PartitionKey='PartitonKey',RowKey='layer1-tileMatrixSet')</id>
        <category term="tablestore.TableName" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" />
        <link rel="edit" title="TableName" href="TableName(PartitionKey='PartitonKey',RowKey='layer1-tileMatrixSet')" />
        <title />
        <updated>2017-03-02T12:01:04Z</updated>
        <author>
            <name />
        </author>
        <content type="application/xml">
            <m:properties>
                <d:PartitionKey>PartitonKey</d:PartitionKey>
                <d:RowKey>RowKey</d:RowKey>
                <d:Timestamp m:type="Edm.DateTime">2017-03-02T11:46:37.1271167Z</d:Timestamp>
                <d:AuthType>basic</d:AuthType>
                <d:Credentials>CREDENTIALS1</d:Credentials>
                <d:Layer>layer1</d:Layer>
                <d:LayerXml>I want this</d:LayerXml>
                <d:Service>https://www.google.co.uk</d:Service>
                <d:TileMatrixSet>tileMatrixSet</d:TileMatrixSet>
            </m:properties>
        </content>
    </entry>
    <entry m:etag="W/&quot;datetime'2017-03-02T11%3A46%3A37.1271167Z'&quot;">
        <id>https://tablestore.somewhere.com/TableName(PartitionKey='PartitonKey',RowKey='layer2-tileMatrixSet')</id>
        <category term="tablestore.TableName" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme" />
        <link rel="edit" title="TableName" href="TableName(PartitionKey='PartitonKey',RowKey='layer2-tileMatrixSet')" />
        <title />
        <updated>2017-03-02T12:01:04Z</updated>
        <author>
            <name />
        </author>
        <content type="application/xml">
            <m:properties>
                <d:PartitionKey>PartitonKey</d:PartitionKey>
                <d:RowKey>RowKey</d:RowKey>
                <d:Timestamp m:type="Edm.DateTime">2017-03-02T11:46:37.1271167Z</d:Timestamp>
                <d:AuthType>basic</d:AuthType>
                <d:Credentials>CREDENTIALS1</d:Credentials>
                <d:Layer>layer2</d:Layer>
                <d:LayerXml>I want this, too</d:LayerXml>
                <d:Service>https://www.google.co.uk</d:Service>
                <d:TileMatrixSet>tileMatrixSet</d:TileMatrixSet>
            </m:properties>
        </content>
    </entry>
</feed>
'''
feed = ET.fromstring(xml)
values = [value.text for value in feed.findall('{http://www.w3.org/2005/Atom}entry/{http://www.w3.org/2005/Atom}content/{http://schemas.microsoft.com/ado/2007/08/dataservices/metadata}properties/{http://schemas.microsoft.com/ado/2007/08/dataservices}LayerXml')]
print(values)

实际上，似乎你也可以使用

values = [value.text for value in feed.findall('.//{http://schemas.microsoft.com/ado/2007/08/dataservices}LayerXml')]

或

values = [value.text for value in feed.findall('.//d:LayerXml', { 'd' : 'http://schemas.microsoft.com/ado/2007/08/dataservices' })]

如果您不想列出完整路径。

获取特定XML emements的值，并将它们添加到Python中的数组中

1 个答案: