Question

我尝试使用put entity/dict嵌套Python进入数据存储区，

metadata_row = dict()
metadata_row['batch_id'] = str(uuid1())
metadata_row['table_ok'] = True
metadata_row['table_name'] = 'metadata'
metadata_row['num_rows'] = 1
metadata_row['violations'] = []
metadata_row['errors'] = []

metadata_row['time'] = {}
metadata_row['time']['total_time'] = 82.42656564712524
metadata_row['time']['mod1'] = 5.940682411193848
metadata_row['time']['mod2'] = 19.16786551475525
metadata_row['time']['mod3'] = 31.617812633514404
metadata_row['time']['mod4'] = 0.00038933753967285156
metadata_row['time']['mod5'] = 53.35780310630798

with self.client.transaction():

    entities = [Entity(self.client.key('metadata')) for i in range(len([metadata_row]))]

    for entity, update_dict in zip(entities, [metadata_row]):
        entity.update(update_dict)

    self.client.put_multi(entities)

我使用datastore emulator测试了它，但是我收到了以下错误，

ValueError: Unknown protobuf attr type <class 'dict'>

我想知道如何解决这个问题。我也想知道datastore本身是否支持嵌套字典，因为不需要为内部字典创建entity，在这种情况下就是time。

更新。我在metadata_row中为密钥time添加了一个内部实体来解决问题。

client = datastore.Client()
metadata_row['time'] = datastore.Entity(key=client.key('time'))

metadata_row['time']['total_time'] = 82.42656564712524
metadata_row['time']['mod1'] = 5.940682411193848
metadata_row['time']['mod2'] = 19.16786551475525
metadata_row['time']['mod3'] = 31.617812633514404
metadata_row['time']['mod4'] = 0.00038933753967285156
metadata_row['time']['mod5'] = 53.35780310630798

# code for put_multi()

Answer 1

def convert(obj, client, key):
"""
:param obj: dict
:param client: datastore client
:param key: Generated as client.key("your_table", "your_key")
:return: datastore.Entity
"""
if isinstance(obj, list):
    return [convert(item, client, None) for item in obj]
elif isinstance(obj, dict):
    entity = datastore.Entity(key)
    for key in obj:
        entity[key] = convert(obj[key], client, None)
    return entity
else:
    return obj

请建议任何改进或替代方案，因为Google Cloud Datastore目前不建议将JSON转换为实体的方法。

ValueError：未知的protobuf attr类型<class'dict'=“”>当试图放置一个嵌套的dict / entity

1 个答案: