插入数据库中的值不正确

时间:2017-02-27 16:22:17

标签: php mysql

我希望用户在点击确认按钮后将所选项目从购物车插入数据库。问题是,在插入项目后,数量值不正确,因为我假设。我希望插入的数量由用户在购物车中确定。但事实是插入的数量是由管理员从数据库中确定的数量库存的值。

以下是查看购物车的代码:

        <table>
        <tr>
            <th>Peralatan Sukan</th>
            <th>Kuantiti</th>
        </tr>
    <?php
            if(isset($_SESSION['cart'])){

 $sql = "SELECT * FROM peralatansukan WHERE no IN(";
        foreach((array) $_SESSION['cart'] as $id => $value){
        $sql .=$id. ",";
        }
        $sql=substr($sql,0,-1) . ") ORDER BY no ASC";
        $query = mysql_query($sql);
        if(!empty($query)){
        while($row = mysql_fetch_array($query)){
?>
<tr>
    <td><?php echo $row['peralatansukan']; ?></td>
    <td><input type="text" name="kuantiti[<?php echo $row['no']; ?>]" 
    size="6" value="<?php echo $_SESSION['cart'][$row['no']]['kuantiti']; ?
    >"> </td>

以下是更新购物车中数量的代码:

if(isset($_GET['action']) && $_GET['action']=="add"){
$id=intval($_GET['id']);
if(isset($_SESSION['cart'][$id])){
    $_SESSION['cart'][$id]['kuantiti']++;
}else{
    $sql_p="SELECT * FROM peralatansukan WHERE no={$id}";
    $query_p=mysql_query($sql_p);
    if(mysql_num_rows($query_p)!=0){
        $row_p=mysql_fetch_array($query_p);
        $_SESSION['cart'][$row_p['no']]=array("kuantiti" => 1);
    }else{
        $message="Product ID is invalid";
    }
}
}

以下是将购物车中的商品插入数据库的代码:

  if(isset($_SESSION['cart'])){
                $sql = "SELECT * FROM peralatansukan WHERE no IN(";
                foreach((array) $_SESSION['cart'] as $id => $value){
                    $sql .=$id. ",";
                }
                $sql=substr($sql,0,-1).") ORDER BY no ASC";
                $query = mysql_query($sql);
                if(!empty($query)){
                    while($row = mysql_fetch_array($query)){
                    $sql="INSERT INTO user_request(nama, noic, jawatan, 
                    peringkat, email, no, peralatansukan, kuantiti) values 
                    ('$_SESSION[nama]', '$_SESSION[noic]',  
                    '$_SESSION[jawatan]', '$_SESSION[peringkat]', 
                    '$_SESSION[email]', '$row[no]', '$row[peralatansukan]', 
                    '$row[kuantiti]')";
                    $res=mysql_query($sql);   
                    unset($_SESSION['cart']);
                    echo '<script type="text/javascript">alert("Your request 
                    is success.");window.location.href="viewalat.php";
                    </script>';
                     }}}
                     else{
                     echo '<script type="text/javascript">alert("Sorry. 
                     Something went  
                     wrong.");window.location.href="viewalat.php";          
                     </script>';
                     }   

我是PHP的新手。希望你能帮我摆脱这个问题。 Fyi,我还在学习使用mysqli。希望你能理解。谢谢。

0 个答案:

没有答案