Question

我有一个名为$ photographerNum的php变量，我希望值的变化取决于我页面上的下拉字段中的值，javascript的样子以及如何接收新值以进行更新php变量？

    <!DOCTYPE html>
<html>
<body>
<? $photographerNum = 1; ?>
<p>Select an item from the list.</p>
<select id="photographerNum" onchange="myFunction()">
  <option value="Item1">Item1
  <option value="Item2">Item2
  <option value="Item3">Item3
  <option value="Item4">Item4
</select>
<script type="text/javascript">
function myFunction() {
    var itemSelected = document.getElementById("photographerNum").value;
    document.getElementById("demo").innerHTML = "You selected: " + itemSelected ;
}
</script>
<p id="demo"> - photoNum=<? echo $photographerNum ?></p>
</body>
</html>

Answer 1

尝试这一点，当您选择一个新项目时，会触发一个表格，输出所选项目的值，之后，您可以发送变量并在服务器端处理它。

<?php 
$photographerNum = 1;
 echo 'Initial value photographerNum::' . $photographerNum;
?>  
 <form name="myform" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" >
   <select name="photographerNum" id="IdphotographerNum"   onchange="myform.submit();">
    <option value="0">Selecte an item
    <option value="1">Item1
    <option value="2">Item2
    <option value="3">Item3
    <option value="4">Item4
</select>
</form>

<?php
if (isset($_POST['photographerNum'])) {
   echo 'New value photographerNum::' . $_POST['photographerNum'];
}
?>

使用ajax中的选择选项列表更改PHP变量值

1 个答案: