Question

我尝试使用php脚本遇到了问题。因此，当我启动它时，脚本完美地连接到MySQL和数据库，但是当我尝试从＆＃39;代码中选择数据时数据库然后它给我一个这样的错误：＆＃34;无法获取数据：＆＃34;。它应该做的是说＆＃34;无法得到数据:(然后是错误）＆＃34;，但它没有。提前致谢。：）

PHP代码：

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database";

// Create connection
$conn = mysqli_connect($servername, $username, $password);
mysqli_select_db($dbname);

// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";

   $sql = 'SELECT code FROM codes';
   $retval = mysql_query( $sql, $conn );

   if(! $retval ) {
      die('Could not get data: ' . mysql_error());
   }

   while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
      echo "Code:{$row['code']}";
   }

   echo "Fetched data successfully\n";

   mysql_close($conn);  
?>

Answer 1

你把mysql和mysqli混合在一起所以我修复了错误：

<?php
ini_set('display_errors', 1); 
error_reporting(E_ALL);
$servername = "localhost";
$username = "root";
$password = "pass";
$dbname = "table";

// Create connection
$conn = mysqli_connect($servername, $username, $password);
        mysqli_select_db($conn, $dbname);

// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
// echo "Connected successfully";

   $sql = 'SELECT username FROM users';
   $retval = mysqli_query($conn ,$sql);

   if(! $retval ) {
      die('Could not get data: ' . mysqli_error());
   }

   while($row=mysqli_fetch_array($retval,MYSQLI_ASSOC)) {
      echo "Code:{$row['username']}";
   }

   echo "Fetched data successfully\n";

   mysqli_close($conn);  
?>

PHP选择MySQL给出未知错误

1 个答案: