Question

我的片段中有一个方法（目的是在点击后将Listview图像更改为另一个图像）。我在我的适配器中调用此方法..现在，当我点击Imageview时没有任何反应..当我再次点击它时它工作..（这个Imageview是一个播放和暂停按钮，所以当我点击它回来把它变成播放icon我必须再次点击两次等等......）..

这是我片段中的方法：

 @Override
public void imageButtonOnClick(View v, int position) {
    playPause=(ImageView)v.findViewById(R.id.playPause);
    Product m = productList.get(position);
    playPause.setImageResource(m.getPlayPauseId());
    playPause.setTag(position);
    playPause.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
                int pos = (Integer) v.getTag();
                Product m =(Product) productList.get(pos);
                if (paused) {
                m.setPlayPauseId(R.drawable.ic_pause);
                paused=false;
                }else {
                 m.setPlayPauseId(R.drawable.ic_play);
                 paused = true;
                }
                adapter.notifyDataSetChanged();     
        }

    });
}

我在我的适配器中这样称呼它：

holder.playPause=(ImageView)v.findViewById(R.id.playPause); 
holder.playPause.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
          if (callback != null) {
              callback.imageButtonOnClick(v, position);
          }      
    }
});

这是我的接口和构造函数，它也在我的适配器中：

public interface PlayPauseClick {
    void imageButtonOnClick(View v, int position);
}
private PlayPauseClick callback;

public void setPlayPauseClickListener(PlayPauseClick listener) {
    this.callback = listener;
}

我在片段

中实现了这个界面

更新

产品类别：

public class Product implements Serializable {


@SerializedName("pid")
public int pid;

@SerializedName("name")
public String name;

@SerializedName("qty")
public int qty;

@SerializedName("price")
public String description;

@SerializedName("image_url")
public String image_url;

@SerializedName("date")
public String date;



 private int PlayPauseId;


public int getPlayPauseId() {
    return PlayPauseId;
}

public void setPlayPauseId(int playPauseId) {
    PlayPauseId = playPauseId;
 }

Answer 1

我认为您不需要发送回Fragment的电话来更改播放/暂停图像然后通知。在适配器中简单地更改它就像

一样

holder.playPause.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        Product product =(Product) productList.get(pos);
        if (product.getPlayPauseId() == R.drawable.ic_play) {
            product.setPlayPauseId(R.drawable.ic_pause);
        }else {
            product.setPlayPauseId(R.drawable.ic_play);
        }
        v.setImageResource(product.getPlayPauseId());
    }
});

<强>更新
在您的情况下，您的所有逻辑代码都在Fragment而不是Adapter，所以我认为您可以这样做适配器

Product product = productList.get(position);
holder.playPause=(ImageView)v.findViewById(R.id.playPause); 
holder.playPause.setImageResource(product.getPlayPauseId());
holder.playPause.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
          if (callback != null) {
              // you need to pass the position, don't need pass the View 
              callback.imageButtonOnClick(position);
          }      
    }
});

片段代码

public void imageButtonOnClick(int position) {
     Product product = productList.get(position);
     if(your logic){
          product.setPlayPauseId(R.drawable.ic_play);
     }else{
          product.setPlayPauseId(R.drawable.ic_pause);
     } 
     adapter.notifyDataSetChanged();
}

两次点击后，ImageView会更改图片

1 个答案: