SQL在特定日期范围内选择生日

Question

我有以下内容：

DECLARE @TempTable TABLE 
(
 [Id] [int],
 [FirstName] [varchar](40) NULL,
 [Birthdate] [date] NULL
);

insert into @TempTable values (1, 'A', convert(date, '05/25/2017', 101))
insert into @TempTable values (2, 'B', convert(date, '06/25/2017', 101))

我需要的是查询，它将返回从StartDate到EndDate的所有生日。

更多信息是我希望得到的结果：

案例1： 如果日期范围设置为：

DECLARE @StartDate datetime = '05/01/2017'; 
DECLARE @EndDate datetime = '07/01/2017';

查询应返回：

1 A 2017-05-25
2 B 2017-06-25

案例2： 如果日期范围设置为：

DECLARE @StartDate datetime = '05/01/2017'; 
DECLARE @EndDate datetime = '06/01/2017';

查询应返回：

1 A 2017-05-25

案例3： 如果日期范围设置为：

DECLARE @StartDate datetime = '05/01/2015'; 
DECLARE @EndDate datetime = '07/01/2017';

查询应返回：

1 A 2017-05-25
1 A 2016-05-25
1 A 2015-05-25
2 B 2017-06-25
2 B 2016-06-25
2 B 2015-06-25

案例4： 如果日期范围设置为：

DECLARE @StartDate datetime = '05/01/2015'; 
DECLARE @EndDate datetime = '06/01/2017';

查询应返回

1 A 2017-05-25
1 A 2016-05-25
1 A 2015-05-25
2 B 2016-06-25
2 B 2015-06-25

Answer 1

首先，我们为给定范围创建所有日期。然后应用逻辑

        DECLARE @StartDate datetime = '05/01/2015'; 
        DECLARE @EndDate datetime = '06/01/2017';

        ;With DateSequence  as
        (
            Select @StartDate as Bdate
            union all
            Select dateadd(day, 1, Bdate)
            from DateSequence
           where Bdate < @EndDate
        )
        Select ID,FirstName,Bdate as BirthDate from DateSequence 
        cross join @TempTable
        where Bdate between @StartDate and @EndDate and
        month(Bdate)= month(BirthDate) and day(Bdate) = day(BirthDate)
        order by ID asc , Bdate desc
        option (MaxRecursion 2000)

  

OutPut：

Answer 2

在最基本的层面上，您可以通过创建100年的每个人的生日列表，然后过滤......

with numbers as
(
select 0 as NN
union all
select NN+1
from numbers
where NN < 100
)    
select id, dateadd(yy,NN,BirthDate) as Birthdays
from numbers
cross join @TempTable
where dateadd(yy,NN,BirthDate) between @StartDate and @EndDate