Question

我正在尝试创建一个包含请求参数的新类，但我收到错误：

上下文类型any不能与数组文字一起使用

我尝试在最后添加as Any，但它无效。

class JsonParams {
    let userName = "root"
    let password = "admin01"

    static let param: [String: Any] = [
        "jsonrpc": "2.0",
        "id": 1,
        "method": "call",
        "params": [
            "00000000000000000000000000000000",
            "session",
            "login",
            [ "username": userName, "password": password]
        ]
    ]
}

修改

现在我需要在有人输入之后从用户名文本字段发送用户名和密码到param，所以我想为param创建一个方法，

class JsonParams {

let userName = "root"
let password = "admin01"
var param = [String: Any]()
func log (username.text, password.text){
init() {
    let param : [String: Any] = ["jsonrpc": "2.0", "id": 1, "method": "call", "params": [ "00000000000000000000000000000000", "session", "login", [ "username": username.text, "password": password.text]]]
    self.param = param
}

Answer 1

未来访客的一般答案

当您尝试将数组分配给不是数组的内容时，可能会发生此类错误。

示例1

let array: Int = [1, 3, 7, 4]
// error: contextual type Int cannot be used with array literal

与其名称相反，常量array被称为单Int。但是然后为它分配了一个实际的数组。这可以通过以下任一方式解决。

let array = [1, 3, 7, 4]
let array: [Int] = [1, 3, 7, 4]

示例2

当有嵌套数组时，它可能不太明显：

let array: [Int] = [1, 2, 7, [100, 200, 300]]
// error: contextual type Int cannot be used with array literal

对于这个，您需要将其概括为[Any]。

let array: [Any] = [1, 2, 7, [100, 200, 300]]

Answer 2

您需要以这种方式初始化对象：

class JsonParams {

    let userName = "root"
    let password = "admin01"
    var param = [String: Any]()

    init() {
        let param : [String: Any] = ["jsonrpc": "2.0", "id": 1, "method": "call", "params": [ "00000000000000000000000000000000", "session", "login", [ "username": self.userName, "password": self.password]]]
        self.param = param
    }
}

修改

如果你想获得userName，你可以这样做：

class JsonParams { let userName = "root" let password = "admin01" var param = [String: Any]() init() { let param : [String: Any] = ["jsonrpc": "2.0", "id": 1, "method": "call", "params": [ "00000000000000000000000000000000", "session", "login", [ "username": self.userName, "password": self.password]]] self.param = param } func getUserName() -> String { return self.userName } }

这样你就可以访问：

let json = JsonParams() json.getUserName() //"root"

Swift上下文类型any不能与数组文字一起使用

2 个答案:

未来访客的一般答案