大家好我想为我的服务器编写一个wol脚本代码。树莓派在每次启动时都会执行。
我猜它是一个语法错误,但我现在不是解决方案,所以我问你。 我在第5行收到错误,但不知道如何纠正错误。
#!/bin/bash
nas=[ping -c 1 192.192.168.222.5 &> /dev/null ]
until [ $nas = "1" ];do
python wol.py
sleep 2
nas=[ping -c 1 192.192.168.222.5 &> /dev/null ]
done
wol.py是发送wol包的marc balmar的脚本
#!/usr/bin/env python
#coding: utf8
# Wake-On-LAN
#
# Copyright (C) 2002 by Micro Systems Marc Balmer
# Written by Marc Balmer, marc@msys.ch, http://www.msys.ch/
# Modified by saarnu for nerdoskop.wordpress.com
# This code is free software under the GPL
import struct, socket, time, os
def WakeOnLan(ethernet_address):
# Construct a six-byte hardware address
addr_byte = ethernet_address.split(':')
hw_addr = struct.pack('BBBBBB', int(addr_byte[0], 16),
int(addr_byte[1], 16),
int(addr_byte[2], 16),
int(addr_byte[3], 16),
int(addr_byte[4], 16),
int(addr_byte[5], 16))
# Build the Wake-On-LAN "Magic Packet"...
msg = '\xff' * 6 + hw_addr * 16
# ...and send it to the broadcast address using UDP
time.sleep(5)
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_BROADCAST, 1)
s.sendto(msg, ('<broadcast>', 9))
s.close()
WakeOnLan('C8:60:00:6D:CF:54') # MAC-Adresse der DiskStation
我在powershell中编写了一个类似的代码,它实际上要复制它或者将它翻译成bash要容易得多。
$NAS = test-connection -count 1 -quiet 192.168.222.5
if ($NAS -like "False"){
do
{
$Mac = "C8:60:00:6D:CF:54"
$MacByteArray = $Mac -split "[:-]" | ForEach-Object { [Byte] "0x$_"}
[Byte[]] $MagicPacket = (,0xFF * 6) + ($MacByteArray * 16)
$UdpClient = New-Object System.Net.Sockets.UdpClient
$UdpClient.Connect(([System.Net.IPAddress]::Broadcast),7)
$UdpClient.Send($MagicPacket,$MagicPacket.Length)
$UdpClient.Close()
Start-Sleep -s 5
$NAS = test-connection -count 1 -quiet 192.168.222.5
}
until
(
$NAS -like "True"
)
}
答案 0 :(得分:1)
首先,使用http://www.shellcheck.net修复脚本中的语法问题。
您的命令替换语法错误,使用该修复并直接在ping
until-loop
的退出代码
until ping -c 1 192.192.168.222.5 &> /dev/null
do
python wol.py
sleep 2
done
应该解决你的问题。 man
的{{1}}页说
如果ping根本没有收到任何回复数据包,它将以代码1退出。如果指定了数据包计数和截止时间,并且在截止日期到达之前收到的数据包数量少于它,则它也将退出代码1.在其他错误上,它以代码2退出。否则它以代码0退出。这使得可以使用退出代码来查看主机是否存活。
答案 1 :(得分:0)
嘿,你的bash脚本中有一些错误,而不只是一个。
#!/bin/bash
# This is a silent ping. The output is redirected to /dev/null. The only visible
# change in user-land will be the exit code, available as $?.
# The exit code "0" means success, the exit code "1" means some error.
ping -c 1 192.192.168.222.5 &> /dev/null
# You need double round parenthesis here to evaluate a comparison.
# Also a comparison, as almost everywhere in programming, is "==" instead of "=".
until (( $? == "0" ));
do
python wol.py
sleep 2
# There is the silent ping again. Updating $?.
ping -c 1 192.192.168.222.5 &> /dev/null
done
有关退出代码,请参阅: Exit Shell Script Based on Process Exit Code
对于不同的括号/括号,请通过man bash
,How to use double or single brackets, parentheses, curly braces或https://stackoverflow.com/a/9666169/7236811查看真正优秀的bash手册。