Question

我需要获得效率数据：

create table #tbl( userid int,workid int,  workstartday int, workendday int, workyear int)

and data
insert into #tbl(userid, workid, workstartday,workendday,workyear) 
values(1,1,2,5,2017),(1,2,3,5,2017),(1,3,4,8,2017)

开始日和结束日是内部工作日

需要输出，显示用户多天的效率

即，

user 1 - 1st day - 0 work
user 1 - 2nd day - 1 work
user 1 - 3rd day - 2 work 
user 1 - 4th day - 3 work
user 1 - 5th day - 3 work
user 1 - 6th day - 1 work
user 1 - 7th day - 1 work

提前感谢您的帮助

Answer 1

首先创建一个包含所有日期的临时表。比计算每天的作品。

;with days_rte as
(
    select min(workstartday) [day],max(workendday) [lastDay]
    from #tbl
    union all
    select a.[day]+1, a.lastDay
    from days_rte a
    where [day] < a.lastDay
)

select t.userid,d.[day],count(t.workid) [work]
from days_rte d
join #tbl t on d.[day] between t.workstartday and t.workendday
group by t.userid,d.[day]

sqlserver - 从周期数据计算并获得效率矩阵

1 个答案: