我无法搜索此问题
我想要正则表达式，我可以允许一组字符所以我想允许字符a到z和package GamePackage;
import java.awt.*;
import java.awt.geom.Rectangle2D;
import java.util.Random;
public class Square {
public int XLocation;
public int Size;
public int YLocation = -Size;
public int fallSpeed = 1;
Random rand = new Random();
int R = rand.nextInt((256-40)+1)+40;
int G = rand.nextInt((256-40)+1)+40;
int B= rand.nextInt((256-40)+1)+40;
Color RandomColour = new Color (R, G, B);
public int generateRandomXLocation(){
return XLocation = rand.nextInt(Game.WINDOW_WIDTH - Size);
}
/*
//creates a random value and stores it in squareWidth
*/
public int generateRandomSquareSize(){
return Size = rand.nextInt((30-17)+1)+17;
}
public int generateRandomFallSpeed(){
return fallSpeed = rand.ints(3, 3, 8).findFirst().getAsInt(); // 3, 3, 8
}
/*
//paints the square with the variables generated in the random methods
*/
public void paint(Graphics g){
g.setColor(RandomColour);
g.fillRect(XLocation,YLocation,Size,Size);
}
/*
//sets the squareWidth and square fallSpeed to a random value for every square created
*/
public Square(){
generateRandomXLocation();
generateRandomSquareSize();
generateRandomFallSpeed();
}
public void update(){
//changes the squares xLocation and fallSpeed if the created square reaches the bottom of the screen
if(YLocation >= Game.WINDOW_HEIGHT){
generateRandomXLocation();
generateRandomFallSpeed();
generateRandomSquareSize();
YLocation = -Size;
}
//moves the square down if the square is inside the window
if(YLocation <= Game.WINDOW_HEIGHT){
YLocation += fallSpeed;
}
}
public Rectangle GetBounds(){
Rectangle rectangle = new Rectangle(XLocation,YLocation,Size,Size);
return rectangle;
}
}
作为一个组我不想允许 和{{1单独但仅作为组
我试过
&但这不起作用，有人可以提供帮助
答案 0 :(得分：2)
字符类中的所有字符都是单个字符。所以：
using UnityEngine;
using UnityEngine.UI;
[AddComponentMenu("UI/CodeText", 10)]
public class CodeText : Text
{
void Awake() {
Game.Instance.trackMe();
}
}
允许
( )
，(，&，n，b，s，p
;有一些例外;范围all characters，领先a-z，用于反转使用情况，元字符^ ......以及其他几个字符。
您可以使用字符类和更改来允许空间实体。
\n如果您想允许更多实体，您可以在实体方面进行更多更改。
([a-z]| )+
这是一个regex101演示：https://regex101.com/r/1FB2bJ/1。