我创建了一个独立的应用程序,我希望当用户点击运行按钮时,终端应该打开,并且应该在终端上执行特定的命令。我可以使用以下代码成功打开终端...
Process process = null;
try {
process = new ProcessBuilder("xterm").start();
} catch (IOException ex) {
System.err.println(ex);
}
上面的代码打开了一个终端窗口,但我无法对其执行任何命令。谁能告诉我怎么做?
答案 0 :(得分:5)
尝试
new ProcessBuilder("xterm", "-e",
"/full/path/to/your/program").start()
答案 1 :(得分:4)
在linux中执行任何命令,就像你在终端中键入的那样:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class CommandExecutor {
public static String execute(String command){
StringBuilder sb = new StringBuilder();
String[] commands = new String[]{"/bin/sh","-c", command};
try {
Process proc = new ProcessBuilder(commands).start();
BufferedReader stdInput = new BufferedReader(new
InputStreamReader(proc.getInputStream()));
BufferedReader stdError = new BufferedReader(new
InputStreamReader(proc.getErrorStream()));
String s = null;
while ((s = stdInput.readLine()) != null) {
sb.append(s);
sb.append("\n");
}
while ((s = stdError.readLine()) != null) {
sb.append(s);
sb.append("\n");
}
} catch (IOException e) {
e.printStackTrace();
}
return sb.toString();
}
}
用法:
CommandExecutor.execute("ps ax | grep postgres");
或复杂如:
CommandExecutor.execute("echo 'hello world' | openssl rsautl -encrypt -inkey public.pem -pubin | openssl enc -base64");
String command = "ssh user@database-dev 'pg_dump -U postgres -w -h localhost db1 --schema-only'";
CommandExecutor.execute(command);
答案 2 :(得分:2)
假设您正在尝试gedit命令,那么您需要提供gedit的完整限定路径(例如/ usr / bin / gedit)。同样,对于所有其他命令,请指定完整路径。