我试图在ReactNative中使用passProps / paramters在Navigation中推送视图。我可以用一些谷歌搜索和其他东西。
下面是我在导航器中推送视图的代码。
export default class LoginScreen extends Component {
constructor() {
super()
this.state = {
email: '',
password: ''
}
}
render() {
return (
<View style={{flex:1, flexDirection:'column', justifyContent: 'center'}}>
<View style={{flexDirection:'column'}}>
<TextInput
style = {styles.input}
placeholder = 'Email'
autoCapitalize = 'none'
onChangeText = { (email) => {alert(this.state.email); this.setState({email})}}
/>
<TextInput
style = {styles.input}
placeholder = 'Password'
autoCapitalize = 'none'
onChangeText = { () => this.updatePassword()}
/>
</View>
<View style={{ marginTop:20, alignItems: 'center'}}>
<TouchableOpacity style={{alignItems: 'center', justifyContent: 'center', borderWidth:1, width:100, height:40}}
onPress={ () => this._onPressButton() } >
<Text >Login</Text>
</TouchableOpacity>
</View>
</View>
);
}
_onPressButton() {
this.props.navigator.push({
name: 'Home',
title: 'Home',
passProps: {
userName: this.state.email,
}
callback: this._callbackFun(''),
});
}
updateEmail = (text) => {
this.setState({email: text})
alert(text)
}
updatePassword = (text) => {
this.setState({password: text})
alert(this.state.password)
}
_callbackFun = (text) => {
alert(text)
}
我想知道如何在导航中使用passProps / parameters弹出视图,以便任何screen1都可以根据screen2上发生的活动更新视图。
下面是我弹出视图的代码。
export default class HomeScreen extends Component {
constructor(props) {
super(props)
}
render() {
return (
<View style={{flex:1, flexDirection:'column', alignItems: 'center', justifyContent: 'center'}}>
<Text>Login Successfully {this.props.userName}!!</Text>
<TouchableOpacity style={{alignItems: 'center', justifyContent: 'center', marginTop:20, borderWidth:1, width:100, height:40}}
onPress={ () => this._onPressButton1('button1') }>
<Text >Button1</Text>
</TouchableOpacity>
<TouchableOpacity style={{alignItems: 'center', justifyContent: 'center', marginTop:20, borderWidth:1, width:100, height:40}}
onPress={ () => this._onPressButton1('button2') }>
<Text >Button2</Text>
</TouchableOpacity>
</View>
)
}
_onPressButton1(buttonName) {
if(buttonName == 'button1')
{
this.props.navigator.pop();
}
else if (buttonName == 'button2') {
this.props.callback();
}
}
但它显示的错误如callback function is undefined
。
任何帮助传递参数或设置回调函数将不胜感激。!!!
答案 0 :(得分:0)
尝试以下
_onPressButton1(buttonName) {
if(buttonName == 'button1')
{
this.props.route.callback(args);
this.props.navigator.pop();
}