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Question

我有2个模型：TheSeries和TheEpisodes。

TheSeries有多个TheEpisodes，TheEpisodes有一个TheSeries。

我正在尝试列出所有TheSeries并使用TheEpisodes.addDate在每个中显示latestEpisode。

我现在的代码是：

$TheSeries = TheSeries::with('TheEpisodes');

我应该怎么做才能为每部电视连续剧只显示最新的一集？

修改

->take(1)和->limit(1)不适用于TheEpisodes

编辑（最新半工作代码）

$results = TheSeries::take(5)->with(['TheEpisodes' => function($q) {
    $q->orderBy('addDate', 'desc');
}])->get()

这样可行，它会以正确的顺序返回剧集，但我无法将结果限制为1.以下代码不起作用：

// Example 1
$results = TheSeries::take(5)->with(['TheEpisodes' => function($q) {
    $q->orderBy('addDate', 'desc')->take(1);
}])->get()
// Example 2
$results = TheSeries::take(5)->with(['TheEpisodes' => function($q) {
    $q->orderBy('addDate', 'desc')->limit(1);
}])->get()
// Example 3
$results = TheSeries::take(5)->with(['TheEpisodes' => function($q) {
    $q->orderBy('addDate', 'desc')->first();
}])->get()

这些是表的列名：

TheSeries - id，originalTitle，aliasTitle，description，imageURL，startingDate，endingDate，activeBool

TheEpisodes：id，seriesID，authorID，addDate，episodeVersion

Answer 1

您可以尝试：

$TheSeries = TheSeries::with(['TheEpisodes' => function($q) {
    $q->orderBy('created_at', 'desc')->take(1);
}])
->get();

或尝试使用limit作为：

$TheSeries = TheSeries::with(['TheEpisodes' => function($q) {
    $q->orderBy('created_at', 'desc')->limit(1);
}])
->get();

Answer 2

在TheLatestEpisode模型上定义hasOne TheSeries关系：

class TheSeries extends Model
{
    public function TheLatestEpisode()
    {
        return $this->hasOne(TheEpisode::class, 'seriesID')->orderBy('id', 'desc');
    }
}

然后你可以很容易地做到：

$series = TheSeries::with('TheLatestEpisode')->get();

Answer 3

$TheSeries = TheSeries::with(['TheEpisodes' => function($q) {
    $q->orderBy('created_at', 'desc')->first();
}])
->get();

无法正常工作？

Answer 4

为什么不使用DB声明？

DB::table('TheEpisodes')
->leftjoin('TheSeries','TheEpisodes.SeriesId','=','TheSeries.id')
->select('TheEpisodes.*','TheSeries.id as sId','TheSeries.name as sName',...)
->orderBy('TheEpisodes. addDate','desc')
->take(1)
->get();

Answer 5

你可以在TheSeries模型中尝试这样的事情:(它更容易）

public function getLatestEpisodeAttribute(){
    $episode = TheEpisodes::where('series_id',$this->attributes['id'])
            ->latest()
            ->first();
    if(!$episode){
        return "no episodes for this Series";
    }
    return $episode;
}

在您的控制器上，只需正常执行查询，不包含与TheSeries相关的任何内容，您可以在刀片文件中访问它，如下所示：

//lets suppose there is a title attibute in the episodes
{{$TheSeries->latest_episode->title}}
//or a duration attribute
{{$TheSeries->latest_episode->duration}}

Answer 6

我找到的最佳解决方案是与orderBy（'addDate'）建立一对一的关系，它有效！

参考：https://softonsofa.com/tweaking-eloquent-relations-how-to-get-latest-related-model/

Answer 7

$TheSeries = TheSeries::with('TheEpisodes')->first();

或者

$TheSeries = TheSeries::with('TheEpisodes')->firstOrFail();

PHP Laravel（ - ＆gt; with）只有1个结果

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编辑（最新半工作代码）

7 个答案: