Question

我想删除启动特定＆＃34; TYPE＆＃34;的列。单词并且不包含_1？

df =

TYPE_1    TYPE_2    TYPE_3    COL1
aaa       asb       bbb       123

结果应为：

df =

    TYPE_1    COL1
    aaa       123

目前我手动删除这些列，但是如果列数很大，这种方法效率不高：

df = df.drop(["TYPE_2","TYPE_3"], axis=1)

Answer 1

可以使用列表理解。注意：axis = 1表示我们指的是列，inplace=True也可以用作pandas.DataFrame.drop个文档。

droplist = [i for i in df.columns if i.startswith('TYPE') and '_1' not in i]
df1.drop(droplist,axis=1,inplace=True)

Answer 2

这是第五个答案，但我想展示package raspberryws; import java.io.IOException; import java.io.InputStream; import javax.ws.rs.GET; import javax.ws.rs.Path; import javax.ws.rs.Produces; @Path("DHTService") public class DHTService { public DHTService() { super(); } @GET @Produces(value = { "application/json" }) @Path("/readDHT") public DHTSensor readDHT11() throws IOException { DHTSensor sensor = new DHTSensor(); int ch; char y; String temp="" ; String humidity="" ; try { Process p = Runtime.getRuntime().exec("sudo python /projects/Adafruit_Python_DHT/examples/AdafruitDHT.py 11 4 "); // get an InputStream for the python stdout InputStream inStream = p.getInputStream(); // read all stdout data one char at a time. while ((ch = inStream.read()) != -1) { System.out.println(ch + " ch"); if ((int) ch == 47) { sensor.setTempreture(temp); humidity=""; } else { if ((int) ch == 10) { continue; } y = (char) ch; temp=temp+y; humidity=humidity+y; sensor.setHumidity(humidity); } } } catch (IOException e) { e.printStackTrace(); } // System.out.println(x); return sensor; }数据框方法的强大功能，该方法按列名称和正则表达式进行过滤。这将搜索不以TYPE开头或在其中某处包含_1的列。

filter

Answer 3

易：

unwanted = [column for column in df.columns 
            if column.startswith("TYPE") and "_1" not in column]
df = df.drop(unwanted)

Answer 4

t_cols = [c for c in df.columns.values if c.startswith('TYPE_') and not c == 'TYPE_1']
df.drop(t_cols)

应该做的工作

如何根据条件删除列

4 个答案: