Question

我有一些问题想出如何从ui-select以多选形式获取所选值。我已经制作了一个片段来告诉你我想做什么。在我的html中，我创建了一个带有ng-change-event回调的ui-select：ng-change="onDatasetChanged(whatShouldBehere?)"。选择该选项后，我只想在控制器中的onDatasetChanged() - 方法内打印所选模型。

angular.module('myApp',['ui.select']).controller('MyController', function ($scope) {
  
  $scope.myUiSelect={model:{}}; // encapsulate your model inside an object.
  $scope.availableData=["a","b","c"]; //some random options
  
  $scope.onDatasetChanged = function(selectedValue){
    console.log("selectedValue",selectedValue);
  }
  
});

<link href="https://rawgit.com/angular-ui/ui-select/master/dist/select.css" rel="stylesheet"/>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<script src="https://rawgit.com/angular-ui/ui-select/master/dist/select.js"></script>
<body ng-app="myApp" ng-controller="MyController">
  
  
  
  <ui-select multiple ng-model="myUiSelect.model" close-on-select="false" title="Choose a dataset" ng-change="onDatasetChanged(whatShouldBehere?)">
    <ui-select-match placeholder="Select something">{{$item.label}}</ui-select-match>
      <ui-select-choices repeat="data in availableData | filter:$select.search">
                        {{data}}
      </ui-select-choices>
  </ui-select>
  
  
  
</body>

Answer 1

对ui-select-directive的存储库页面进行了一些研究之后我想你可以像这样使用on-select事件绑定： on-select="onSelect($item, $model)"。请参阅更新的代码段：

＆＃13;

angular.module('myApp',['ui.select']).controller('MyController', function ($scope) {
  
  $scope.myUiSelect={model:{}}; // encapsulate your model inside an object.
  $scope.availableData=["a","b","c"]; //some random options
  
  $scope.onSelect = function(item,model){
    console.log("selectedItem",item);
  }
  
});

＆＃13;

<link href="https://rawgit.com/angular-ui/ui-select/master/dist/select.css" rel="stylesheet"/>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<script src="https://rawgit.com/angular-ui/ui-select/master/dist/select.js"></script>
<body ng-app="myApp" ng-controller="MyController">
  
  
  
  <ui-select multiple ng-model="myUiSelect.model" close-on-select="false" title="Choose a dataset" on-select="onSelect($item, $model)">
    <ui-select-match placeholder="Select something">{{$item.label}}</ui-select-match>
      <ui-select-choices repeat="data in availableData | filter:$select.search">
                        {{data}}
      </ui-select-choices>
  </ui-select>
  
  
  
</body>

＆＃13;

如何从ui-select multiple中获取所选选项

1 个答案: