通过isset()后,私有静态变量立即未定义

时间:2016-12-19 19:15:04

标签: php laravel-5.3 php-7

我遇到一个非常奇怪的问题,我在通过Undefined variable: authenticated_function调用后立即抛出isset()异常。代码:

class AuthService
{
    static $authenticated_function;

    public static function setAuthenticatedFunction($func)
    {
        \Log::info("Function Set");
        self::$authenticated_function = $func;
    }

    public function authenticated()
    {
        \Log::info("ISSET: " . isset(self::$authenticated_function));
        var_dump(self::$authenticated_function);
        if(isset(self::$authenticated_function))
            self::$authenticated_function(); //Exception is thrown here
    }
}

在我的日志文件中:

[2016-12-19 19:05:08] local.INFO: Function Set  
[2016-12-19 19:05:08] local.INFO: ISSET: 1

var_dump()

object(Closure)[103]
  public 'this' => 
    object(App\Providers\AppServiceProvider)[86]
      ... //Removed for brevity
  protected 'defer' => boolean false

PHP 7.0.8

Laravel 5.3

1 个答案:

答案 0 :(得分:2)

你有这个错误,因为PHP尝试执行你的指令:

  

self:: + [ $authenticated_function + () ]

因此,您的变量不存在...... Undefined variable: authenticated_function

如果要执行该功能,可以使用以下方式:

$func = self::$authenticated_function;
$func();

或更好:

call_user_func(self::$authenticated_function /*, $param1, $param2*/);
// or
call_user_func_array(self::$authenticated_function /*, [$param1, $param2]*/);

:)