Question

我正在尝试从MYSQL打印文章列表，但我一直收到错误。

while($row  = mysql_fetch_assoc($query)){
    echo "<article class='post'>
                <h2><a style='color:#43484d' href='' " .$row['url']. ";</a></h2>
                    <ul class='meta'>
                        <li><span>level :</span> <span style='color:red'>" .$row['Level']. " </span></li>
                        <li><span>Negative votes by visitors :</span> " .$row['negativeVotes']. "</li>
                        <li><span>Positive votes by visitors :</span>" .$row['positiveVotes']. "</li>
                        <li><span  style='color:#000; cursor:pointer' class='fa fa-thumbs-o-up'></span></li>
                        <li><span  style='color:#000; cursor:pointer' class='fa fa-thumbs-o-down'></span></li>
                    </ul>
              </article>"
          }

    ?>

我收到了这个

解析错误：语法错误，意外＆＃39;}＆＃39;，期待＆＃39;，＆＃39;或者＆＃39 ;;＆＃39;。

我做错了什么？非常感谢！

Answer 1

你错过了半结肠。

while($row  = mysql_fetch_assoc($query)){
    echo "<article class='post'>
                <h2><a style='color:#43484d' href='' " .$row['url']. ";</a></h2>
                    <ul class='meta'>
                        <li><span>level :</span> <span style='color:red'>" .$row['Level']. " </span></li>
                        <li><span>Negative votes by visitors :</span> " .$row['negativeVotes']. "</li>
                        <li><span>Positive votes by visitors :</span>" .$row['positiveVotes']. "</li>
                        <li><span  style='color:#000; cursor:pointer' class='fa fa-thumbs-o-up'></span></li>
                        <li><span  style='color:#000; cursor:pointer' class='fa fa-thumbs-o-down'></span></li>
                    </ul>
              </article>";
          }

    ?>

PHP - 从mysql查询中回显html代码和变量

1 个答案: