Question

例如：在MySql中我有column1和column2。如何进行sql查询，返回包含第1列或第2列中所有搜索词的所有记录。到目前为止我一直在使用：

Select * from table1 where (column1 like '%search from input box%' or column2 like '%search from input box%')

Answer 1

如果您的表格为MyISAM：

SELECT  *
FROM    table1
WHERE   MATCH(column1) AGAINST ('+search +from +input +box' IN BOOLEAN MODE)
UNION
SELECT  *
FROM    table2
WHERE   MATCH(column2) AGAINST ('+search +from +input +box' IN BOOLEAN MODE)

在FULLTEXT INDEX和column1（独立）上创建column2，以便快速开展工作，并调整@ft_min_word_len以匹配您需要的字词。

如果不是MyISAM：

SELECT  *
FROM    table
WHERE   (
        column1 RLIKE '[[:<:]]search[[:>:]]'
        AND column1 RLIKE '[[:<:]]from[[:>:]]'
        AND column1 RLIKE '[[:<:]]input [[:>:]]'
        AND column1 RLIKE '[[:<:]]box[[:>:]]'
        )
        OR
        (
        column2 RLIKE '[[:<:]]search[[:>:]]'
        AND column2 RLIKE '[[:<:]]from[[:>:]]'
        AND column2 RLIKE '[[:<:]]input [[:>:]]'
        AND column2 RLIKE '[[:<:]]box[[:>:]]'
        )

Mysql匹配column1或column2中的所有单词

1 个答案: