我意识到我的代码太冗长而且难以阅读。
你能检查我传递参数和在主体中构造参数的方式吗? 本质上,假设我有正确的“生成”和“消费”函数的实现,我想传递一个共享的循环队列和信号量和互斥量到每个生成/消费线程。
typedef struct circularQueue
{
int *items;
int *head;
int *tail;
int numProduced;
int numConsumed;
} circularQueue;
typedef struct threadArg
{
int id;
circularQueue *queue;
pthread_mutex_t *mutex;
sem_t *spaces;
sem_t *itemAvail;
int numItems;
int bufferSize;
int numProducer;
int numConsumer;
} threadArg;
pthread_t *producerThd;
pthread_t *consumerThd;
int main(int argc, char* argv[])
{
pthread_attr_t attr;
// In fo to pass to thread arg
circularQueue *myQueue;
pthread_mutex_t useSharedMem;
sem_t spaces;
sem_t itemAvail;
int numItems;
int bufferSize;
int numProducer;
int numConsumer;
int i, j, k, l;
if(argc != 5)
{
printf("Enter in 4 arguments - N B P C\n");
return -1;
}
numItems = atoi(argv[1]);
bufferSize = atoi(argv[2]);
numProducer = atoi(argv[3]);
numConsumer = atoi(argv[4]);
if(numItems == 0 || bufferSize == 0 || numProducer == 0 || numConsumer == 0)
{
printf("Parameters should not be 0\n");
return -1;
}
// Initialize list of threads
producerThd = malloc(sizeof(pthread_t) * numProducer);
consumerThd = malloc(sizeof(pthread_t) * numConsumer);
// Initialize semaphores
sem_init(&spaces, 0, bufferSize);
sem_init(&itemAvail, 0, 0);
// Initialize mutex
pthread_mutex_init(&useSharedMem, NULL);
// Initialzie thread attributes
pthread_attr_init(&attr);
pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_JOINABLE);
// Initialize queue
myQueue = (circularQueue*)malloc(sizeof(circularQueue));
myQueue->items = (int*)malloc(sizeof(int)*bufferSize);
myQueue->head = myQueue->items;
myQueue->tail = myQueue->items;
myQueue->numProduced = 0;
myQueue->numConsumed = 0;
// thread arguments
for(i = 0; i < numProducer; i++)
{
// Initialize thraed args
threadArg *args = (threadArg*)malloc(sizeof(threadArg));
args->queue = (circularQueue*)malloc(sizeof(circularQueue));
args->mutex = &useSharedMem;
args->spaces = &spaces;
args->itemAvail = &itemAvail;
args->numItems = numItems;
args->bufferSize = bufferSize;
args->numProducer = numProducer;
args->numConsumer = numConsumer;
args->id = i;
pthread_t thisThread = *(producerThd + i);
pthread_create(&thisThread, &attr, produce, args);
}
for(j = 0; j < numConsumer; j++)
{
// Initialize thraed args
threadArg *args = (threadArg*)malloc(sizeof(threadArg));
args->queue = (circularQueue*)malloc(sizeof(circularQueue));
args->mutex = &useSharedMem;
args->spaces = &spaces;
args->itemAvail = &itemAvail;
args->numItems = numItems;
args->bufferSize = bufferSize;
args->numProducer = numProducer;
args->numConsumer = numConsumer;
args->id = j;
pthread_t thisThread = *(consumerThd + i);
pthread_create(&thisThread, &attr, consume, args);
}
for(k = 0; k < numProducer; k++)
{
pthread_join(*(producerThd+k), NULL);
}
printf("Finished waiting for producers\n");
for(l = 0; l < numConsumer; l++)
{
pthread_join(*(consumerThd+l), NULL);
}
printf("Finished waiting for consumers\n");
free(producerThd);
free(consumerThd);
free(myQueue->items);
free(myQueue);
sem_destroy(&spaces);
sem_destroy(&itemAvail);
fflush(stdout);
return 0;
}
谢谢
答案 0 :(得分:0)
您的代码中存在多个未定义行为的来源,您要么在不启用编译警告的情况下进行编译,要么在我认为最差的情况下忽略它们。
中的
printf()
说明符错误
printf("cid %d found this item %d as valid item %d\n", myArgs->id, thisItem, validItem);
因为validItem
是double
,所以最后一个说明符应为%f
。
您的线程函数永远不会返回值,但您声明它们返回void *
,这是此类函数所需的签名。
您正在释放myQueue
函数中的main()
,但尚未对其进行初始化,因为该代码已被注释。
您的代码也难以阅读,因为您没有一致的样式,并且您将声明与语句混合在一起,这使得一切都非常混乱,例如:确定变量的范围非常困难。
修复代码不仅可以帮助其他人阅读,还可以帮助您解决问题并快速找到问题。