Question

我有一个复杂的嵌套XML（从C＃实体图生成），例如：

<Customers>
  <Customer>
    <Id>1</Id>
    <Number>12345</Number>
    <Addresses>
      <Address>
        <Id>100</Id>
        <Street>my street </street>
        <city>London</city>
      </Address>
      <Address>
        <Id>101</Id>
        <street>my street 2</street>
        <city>Berlin</city>
      </Address>
    </Addresses>
    <BankDetails>
      <BankDetail>
        <Id>222</Id>
        <Iban>DE8439834934939434333</Iban>
      </BankDetail>
      <BankDetail>
        <Id>228</Id>
        <Iban>UK1237921391239123213</Iban>
      </BankDetail>
    </BankDetails>
    <Orders>
      <Order>         
        <OrderLine>         
        </OrderLine>
      </Order>
    </Orders>
  </Customer>
</Customers>

在将上述XML数据保存到实际表中之前，我需要先处理它。出于这个原因，我创建了相应的表类型。这些表类型中的每一个都有一个额外的列（guid为ROWGUID），因此如果我正在处理新数据（尚未分配主键），我会生成一个唯一键。我使用此列来保持不同表类型之间的关系完整性。

将上述嵌套XML转换为相应表的SQL语法是什么，请记住子记录必须引用生成的父guid？

Answer 1

试试这样：

DECLARE @xml XML=
N'<Customers>
  <Customer>
    <Id>1</Id>
    <AccountNumber>12345</AccountNumber>
    <Addresses>
      <Address>
        <Id>100</Id>
        <street>my street&gt;</street>
        <city>London</city>
      </Address>
      <Address>
        <Id>101</Id>
        <street>my street&gt;</street>
        <city>Berlin</city>
      </Address>
    </Addresses>
    <BankDetails>
      <BankDetail>
        <Id>222</Id>
        <Iban>DE8439834934939434333</Iban>
      </BankDetail>
      <BankDetail>
        <Id>228</Id>
        <Iban>UK1237921391239123213</Iban>
      </BankDetail>
    </BankDetails>
    <Orders>
      <Order>
        <OrderLine />
      </Order>
    </Orders>
  </Customer>
</Customers>';

- 此查询将创建一个包含所有数据的表#tmpInsert

SELECT cust.value('Id[1]','int') AS CustomerID
      ,cust.value('AccountNumber[1]','int') AS CustomerAccountNumber
      ,addr.value('Id[1]','int') AS AddressId
      ,addr.value('street[1]','nvarchar(max)') AS AddressStreet
      ,addr.value('city[1]','nvarchar(max)') AS AddressCity
      ,bank.value('Id[1]','int') AS BankId
      ,bank.value('Iban[1]','nvarchar(max)') AS BankIban
      ,ord.value('OrderLine[1]','nvarchar(max)') AS OrderLine
INTO #tmpInsert
FROM @xml.nodes('/Customers/Customer') AS A(cust)
OUTER APPLY cust.nodes('Addresses/Address') AS B(addr)
OUTER APPLY cust.nodes('BankDetails/BankDetail') AS C(bank)
OUTER APPLY cust.nodes('Orders/Order') AS D(ord);

- 您可以在这里查看内容

SELECT * FROM #tmpInsert;

- 清理

GO
DROP TABLE #tmpInsert

一旦您获得了表格中的所有数据，您就可以使用简单的DISTINCT，GROUP BY，如果需要，ROW_NUMBER() OVER(PARTITION BY ...)分别为正确插入选择每个集合。

如何将嵌套XML转换为相应的表？

1 个答案: