Question

我遇到了Spring REST Web服务的问题。当我尝试发布JSON时，我总是得到404错误。获取请求工作正常，但不发布。在互联网上搜索但找不到类似的问题。也许你们可以帮助我。这是我的代码：

控制器：

from itertools import product
from random import shuffle 
all_cards = list(product(PIPS, SUITES))

shuffle(all_cards)

just_10_cards = all_cards[:10]
for p, suite in just_10_cards:
    print(p, suite, end='')
print()

}

型号：

package com.java.rest;
import com.java.dto.IncomingTemperature;
import com.java.dto.SensorsTemperature;
import com.java.service.GetSensorsTemperature;
import com.java.service.TemperatureService;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.*;


@RestController
@RequestMapping("/rest")
public class TemperatureRestController {

final static Logger logger = LoggerFactory.getLogger(TemperatureRestController.class);

@Autowired
TemperatureService temperatureService;
@Autowired
GetSensorsTemperature sensorService;

@RequestMapping(value = "/temperature", method = RequestMethod.POST, produces = "application/json")
@ResponseBody
public ResponseEntity<?> addTemperature(@RequestBody IncomingTemperature temperature){
    logger.info("Temperature: {} recieved", temperature);
    temperatureService.addTemperature(temperature);
    return new ResponseEntity<HttpStatus>(HttpStatus.CREATED);
}

@RequestMapping(value = "/temperature/{sensorId}", method = RequestMethod.GET, produces = "application/json")
public SensorsTemperature getTemperature(@PathVariable("sensorId") Long sensorId){
    logger.info("Getting temperatures for sensor{}", sensorId);
    return sensorService.getSensorsTemperature(sensorId);
}

的pom.xml：

package com.java.dto;


import com.fasterxml.jackson.annotation.JsonFormat;

import java.io.Serializable;
import java.util.Date;

public class IncomingTemperature implements Serializable{

    private long sensorId;

    private double temperature;

    @JsonFormat(shape= JsonFormat.Shape.STRING, pattern="yyyy-MM-dd HH:mm:ss")
    private Date date;

    public long getSensorId() {
        return sensorId;
    }

    public void setSensorId(long sensorId) {
        this.sensorId = sensorId;
    }

    public double getTemperature() {
        return temperature;
    }

    public void setTemperature(double temperature) {
        this.temperature = temperature;
    }

    public Date getDate() {
        return date;
    }

    public void setDate(Date date) {
        this.date = date;
    }

我发布的Json：

 <?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>com.java</groupId>
    <artifactId>knowyourheat</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <packaging>jar</packaging>

    <name>KnowYourHeat</name>
    <description>Application for temperature monitoring</description>

    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>1.4.0.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>

    <properties>
        <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
        <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
        <java.version>1.8</java.version>
    </properties>

    <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-data-jpa</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-security</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-thymeleaf</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>

        <dependency>
            <groupId>mysql</groupId>
            <artifactId>mysql-connector-java</artifactId>
            <scope>runtime</scope>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-mail</artifactId>
        </dependency>

        <dependency>
            <groupId>javax.mail</groupId>
            <artifactId>mail</artifactId>
            <version>1.4.3</version>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>


</project>

编辑：

我得到的错误：

{
 "sensorId" : 1,
 "temperture" : 20,
 "date" : "2016-10-20 22:10:10"
}

提前谢谢！

编辑2：

我刚刚使用相同的控制器创建了新项目，一切正常。正如我发现问题是弹簧安全性，出于某种原因，即使我允许所有请求，Post和Put方法也不起作用。这就是我的问题。

Answer 1

尝试添加＆＃34;消耗=＆＃34; application / json＆＃34;在你的@RequestMapping中：

@RequestMapping(value = "/temperature", method = RequestMethod.POST, produces = "application/json", consumes="application/json")

Answer 2

尝试添加＆＃34; headers =＆＃34; Accept = application / json＆＃34;＆＃34;在你的RequestMapping中这样：

@RequestMapping(value = "/temperature", method = RequestMethod.POST, headers = "Accept=application/json")

Answer 3

使用@RestController时，您在方法中不需要@ResponseBody。您获得404因为该方法无法接受任何类型的正文内容。当该方法仅从HTTP请求接收内容但未发回任何正文内容时，您只需要consumes。 ResponseEntity<xxx>定义除了HttpStatus之外该方法将返回的正文内容。如果它不返回正文内容而只返回HttpStatus，则必须使用ResponseEntity<Void>。请尝试以下

@RequestMapping(value = "/temperature", method = RequestMethod.POST, consumes = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<Void> addTemperature(@RequestBody IncomingTemperature temperature){
    logger.info("Temperature: {} recieved", temperature);
    temperatureService.addTemperature(temperature);
    return new ResponseEntity<Void>(HttpStatus.CREATED);
}

现在你应该在客户端获得HttpStatus 201 Created。

Java Spring REST Get工作得很好，但是当发布json时我得到404错误

3 个答案: