Question

我试图在php中填充下拉列表。它没有向我显示下拉列表中的值。但当我看到它的来源时，它正在向我展示。当我看到它的来源时，它会向我展示像这样的价值

<select name="choose" id="chooseme">
  Urban Striped Sleeveless<option value="48514" name=""> </option>Black Leather High Top Sneakers<option value="19264" name=""> </option>Navy Knit Cardigan<option value="19263" name=""> </option>.....

以下是我正在使用的代码..

<?php
      var_dump($_GET["id"]);

      $args = array( 'post_type' => array('product') ,'posts_per_page' => 100);
      $loop = new WP_Query( $args );

      while ( $loop->have_posts() ) : 
          $loop->the_post();
         //echo '<option value="one">one</option>';
            $title = the_title();
            $value =$loop->post->ID;
       echo "<option value='$value'> $title </option>";

      endwhile;
      ?>

Answer 1

请理解下拉工作：

<select name="drpDown">
<option value="1">One</option>
<option value="2">Two</option>
</select>

// here value is what we get when we refer it using its name "drpDown" and the text passed between <option> #### </option> is the text that is shown in drop down.

Answer 2

尝试使用此方法以避免引用

之间的混淆

<?php
          var_dump($_GET["id"]);

          $args = array( 'post_type' => array('product') ,'posts_per_page' => 100);
          $loop = new WP_Query( $args );

          while ( $loop->have_posts() ) : 
              $loop->the_post();
             //echo '<option value="one">one</option>';
                $title = the_title();
                $value =$loop->post->ID;
                ?>
         <option value='<?php echo $value; ?>'> <?php echo $the_title; ?> </option>
    <?php
          endwhile;
          ?>

Answer 3

我认为你有语法错误！

尝试始终使用变量：

".$variable."

在你的情况下：

echo "<option value='".$value."'>" .$title. "</option>";

Answer 4

?php
  var_dump($_GET["id"]);

  $args = array( 'post_type' => array('product') ,'posts_per_page' => 100);
  $loop = new WP_Query( $args );

  while ( $loop->have_posts() ) : 
      $loop->the_post();
     //echo '<option value="one">one</option>';
        $title = the_title();
        $value =$loop->post->ID;
   echo "<option value='$value'> ".$title."</option>";

  endwhile;
  ?>

Answer 5

使用以下提及的代码： array（'product'），'posts_per_page'=＆gt; 100）; $ loop = new WP_Query（$ args）;

          while ( $loop->have_posts() ) : 
              $loop->the_post();
                $title = the_title();
                $value =$loop->post->ID; ?>
           <option value="<?php echo $value; ?>"> <?php echo $title; ?> </option>
    <?php
          endwhile;
          ?>
</html>

Answer 6

尝试使用以下代码。当您使用将打印值的get_the_title()时，您需要检索the_title()之类的标题值

<?php
      var_dump($_GET["id"]);

      $args = array( 'post_type' => array('product') ,'posts_per_page' => 100);
      $loop = new WP_Query( $args );

      while ( $loop->have_posts() ) : 
          $loop->the_post();
         //echo '<option value="one">one</option>';
            $title = get_the_title(); // this will return the value of title
            $value = $loop->post->ID;
       echo "<option value='$value'> $title </option>";

      endwhile;
      ?>

参考链接

https://developer.wordpress.org/reference/functions/get_the_title/ https://codex.wordpress.org/Function_Reference/the_title

Answer 7

Just to avoid confusion, please separate the HTML and PHP. Like this:

<?php
      var_dump($_GET["id"]);

      $args = array( 'post_type' => array('product') ,'posts_per_page' => 100);
      $loop = new WP_Query( $args );
      $posts = "";
      while ( $loop->have_posts() ) : 
          $loop->the_post();
          $title = the_title();
          $value =$loop->post->ID;
          $posts .= "<option value='" . $value . "'>" . $title . "</option>";

      endwhile;
?>

<select name="choose" id="chooseme">
    <?php echo $posts; ?>
</select>

希望它有所帮助。

名称未显示在下拉列表中

7 个答案: