Question

我必须做一个程序，检查4号字符串中是否有重复的数字。问题是，80％的时间程序将无效的数字分类为无效的数字。

import random
def extraction():
    random_number = str(random.randint(1000,9999))
    print(random_number)
    for number in random_number:
        n = 0
        print("number1 ",number)
        for number2 in random_number:
            print("number2 ",number2)
            if(number == number2):
                n = n + 1
                print("n ",n)
                if(n == 2):
                    print("The extracted number is not valid.\n")
                    extraction()

Answer 1

为什么不从数字字符串中创建set()并评估集合的长度？如果有重复的数字，则只有一个条目存储在集合

中

if len(set(str(random_number))) == 4:
   pass #you have 4 unique digits

工作原理示例：

>>> set('1234')
set(['1', '3', '2', '4'])
>>> set('1123')
set(['1', '3', '2'])

Answer 2

为什么不使用str.count()功能？

def extraction():
    random_number = str(random.randint(1000,9999))
    print(random_number)
    if any([random_number.count(i)>1 for i in random_number]):
        print("The extracted number is not valid.\n")
        extraction()

我的程序没有检查字符串中是否有正确的重复

2 个答案: