我想在多个域/网站上运行一个django项目。每个网站都需要访问一个独特的" urls.py" /" views.py"。我已经用this tutorial尝试了它,但它对我不起作用。 有没有办法以简单的方式使用中间件(没有Sites框架)? 一点点帮助真的很棒。感谢。
编辑:正如我在上面的教程中尝试的那样,我的httpd.conf看起来像这样:
ServerRoot "/home/webfactionusername/webapps/erdbeer/apache2"
LoadModule authz_core_module modules/mod_authz_core.so
LoadModule dir_module modules/mod_dir.so
LoadModule env_module modules/mod_env.so
LoadModule log_config_module modules/mod_log_config.so
LoadModule mime_module modules/mod_mime.so
LoadModule rewrite_module modules/mod_rewrite.so
LoadModule setenvif_module modules/mod_setenvif.so
LoadModule wsgi_module modules/mod_wsgi.so
LoadModule unixd_module modules/mod_unixd.so
LogFormat "%{X-Forwarded-For}i %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined
CustomLog /home/webfactionusername/logs/user/access_erdbeer.log combined
ErrorLog /home/webfactionusername/logs/user/error_erdbeer.log
Listen 10414
KeepAlive Off
SetEnvIf X-Forwarded-SSL on HTTPS=1
ServerLimit 1
StartServers 1
MaxRequestWorkers 5
MinSpareThreads 1
MaxSpareThreads 3
ThreadsPerChild 5
WSGIDaemonProcess erdbeer processes=2 threads=12 python-path=/home/webfactionusername/webapps/erdbeer:/home/webfactionusername/webapps/erdbeer/myproject:/home/webfactionusername/webapps/erdbeer/lib/python2.7
WSGIProcessGroup erdbeer
WSGIRestrictEmbedded On
WSGILazyInitialization On
WSGIScriptAlias / /home/webfactionusername/webapps/erdbeer/myproject/myproject/wsgi.py
# Virtual hosts setup
NameVirtualHost *
<VirtualHost *>
ServerName mydomain123abc.de
WSGIDaemonProcess erdbeer processes=5 python-path=/home/webfactionusername/webapps/erdbeer:/home/webfactionusername/webapps/erdbeer/lib/python2.7 threads=1
WSGIScriptAlias / /home/webfactionusername/webapps/erdbeer/subdomain1.wsgi
</VirtualHost>
<VirtualHost *>
ServerName seconddomain123.de
WSGIDaemonProcess erdbeer processes=5 python-path=/home/webfactionusername/webapps/erdbeer:/home/webfactionusername/webapps/erdbeer/lib/python2.7 threads=1
WSGIScriptAlias / /home/webfactionusername/webapps/erdbeer/subdomain2.wsgi
</VirtualHost>
Edit2:我仍然无法掌握这个中间件概念。我只能理解我可能需要使用&#34; process_request&#34;,但我不知道中间件文件是怎么样的。可以说我有&#34; domain1.com&#34;和&#34; domain2.com&#34;应该使用这些网址:
domain1_urls.py
from django.conf.urls import include, url
from django.contrib import admin
from django.http import HttpResponse
urlpatterns = [
url(r'^$', 'myapp1.views.home'),
url(r'^admin/', include(admin.site.urls)),
url(r'^robots\.txt$', lambda r: HttpResponse("User-agent: *\nDisallow:", content_type="text/plain")),
]
domains2_urls.py
from django.conf.urls import include, url
from django.contrib import admin
from django.http import HttpResponse
urlpatterns = [
url(r'^$', 'myapp2.views.home'),
url(r'^admin/', include(admin.site.urls)),
url(r'^robots\.txt$', lambda r: HttpResponse("User-agent: *\nDisallow:", content_type="text/plain")),
]
我如何在我的中间件中使用它? (我是初学者......)
答案 0 :(得分:0)
我找到了解决方案perfectly here。
# File: settings.py
HOST_MIDDLEWARE_URLCONF_MAP = {
# Control Panel
"www.example.com": "webapp.sites.example.urls",
}
和
# File: multihost.py
import time
from django.conf import settings
from django.utils.cache import patch_vary_headers
class MultiHostMiddleware:
def process_request(self, request):
try:
request.META["LoadingStart"] = time.time()
host = request.META["HTTP_HOST"]
#if host[-3:] == ":80":
# host = host[:-3] # ignore default port number, if present
# best way to do this.
host_port = host.split(':')
if len(host_port)==2:
host = host_port[0]
if host in settings.HOST_MIDDLEWARE_URLCONF_MAP:
request.urlconf = settings.HOST_MIDDLEWARE_URLCONF_MAP[host]
request.META["MultiHost"] = str(request.urlconf)
else:
request.META["MultiHost"] = str(settings.ROOT_URLCONF)
except KeyError:
pass # use default urlconf (settings.ROOT_URLCONF)
def process_response(self, request, response):
if 'MultiHost' in request.META:
response['MultiHost'] = request.META.get("MultiHost")
if 'LoadingStart' in request.META:
_loading_time = time.time() - int(request.META["LoadingStart"])
response['LoadingTime'] = "%.2fs" % ( _loading_time, )
if getattr(request, "urlconf", None):
patch_vary_headers(response, ('Host',))
return response