如何使用用户输入在Java中填充2D数组?

时间:2016-10-14 03:30:35

标签: java arrays multidimensional-array

我试图通过使用用户输入的字符串在Java中填充二维数组。我已经有了字符串,我已经想出了如何创建数组。我只是在弄清楚如何将值放入数组中。如果您想知道,是的,我必须使用数组。以下是我到目前为止的情况:

    private static int[][] parseTwoDimension(String strInput)
        {
            int rows = 0; //number of rows in the string

            for (int i = 0; i < strInput.length(); i++)
            {
                if (strInput.charAt(i) == '!') //the ! is an indicator of a new row
                {
                    rows++;
                }
            }

            int[][] arr = new int[rows][]; //create an array with an unknown number of columns
            int elementCounter = 0; //keep track of number of elements
            int arrayIndexCounter = 0; //keep track of array index

            for (int i = 0; i < strInput.length(); i++)
            {
                if (strInput.charAt(i) != '!') //while not the end of the row
                {
                    elementCounter++; //increase the element count by one
                }
                else //reached the end of the row
                {
                    arr[arrayIndexCounter] = new int[elementCounter]; //create a new column at the specified row
                    elementCounter = 0; //reset the element counter for the next row
                    arrayIndexCounter++; //increase the array index by one
                }
            }
        /*
        This is where I need the help to populate the array
        */
        char c; //each character in the string
        int stringIndex = -1; //keep track of the index in the string
        int num; //the number to add to the array
        for (int i = 0; i < arr.length; i++)
        {
            for (int j = 0; j < arr[i].length; j++)
            {
                stringIndex++; //increment string index for next element
                c = strInput.charAt(stringIndex); //the character at stringIndex
                if (c == '!') //if it is the end of the row, do nothing
                {

                }
                else //if it is not the end of the row...
                {
                    String s = Character.toString(c); //convert character to String
                    num = Integer.parseInt(s); //convert String to Integer
                    arr[i][j] = num; //add Integer to array
                }
            }
        }
        return arr; //return a two dimensional array the user defined
    }

非常感谢任何帮助:)

1 个答案:

答案 0 :(得分:2)

我已编辑您的代码并将其发布在下方。这是如何解决它的大致概述:

  1. 使用string.split(“!”)通过分隔符'!'分隔String。这将返回一个数组

  2. 然后,使用string.split(“”)将字符串分隔成单个字符

  3. 以下代码:

    private static int[][] parseTwoDimension(String strInput)
    {
        String[] rows = strInput.split("!");    
        int[][] arr = new int[rows.length()][];
    
        for(int i = 0; i < rows.length; i++)
        {
            String[] elements = rows[i].split("");
            int[] intElements = new int[elements.length];
    
            for(int j = 0; j < elements.length; j++)
            {
                intElements[j] = Integer.parseInt(elements[j]);
            }
            arr[i] = intElements;
        }
    }
    

    如果有效,请告诉我。将字符串解析为数组时,string.split()函数非常有用