Question

大家早上好！

我正在处理PHP脚本，允许用户选择符合以下格式的文本文件并将其转换为xml文件。

文字档案

Barcode:                           9091
Update Bib Status:                 Unable to update bib record: item barcode not found.
Update Holding Status:             Unable to update holdings record: item barcode not found.
Update Item Status:                Unable to update item record: item barcode not found.

Item ID:                           int
Barcode:                           int
Title:                             some stuff
Enum/Chron:                        
Call Number:                       alphanumeric stuff
Call Number Prefix:                
Holding Location:                  some stuff
Permanent Location:                some stuff
Temporary Location:                some stuff
Permanent Type:                    some stuff
Temporary Type:                    
Media Type:                        
Item Status:                       Not Charged
Statistical Categories:            
Magnetic Media:                    No
Sensitize:                         Yes

我想获取左栏中的信息，并将它们用作XML元素，将右栏中的项目用作内容。 Soo ....我希望在运行脚本后输出的输出将是一个像这样的xml文件：

<item>
<barcode>9091</barcode>
<ItemID>1234</ItemID>
<title>In the heart of the Sea</title>
....
</item>

我能够上传文件，但是我仍然坚持创建所需的元素。

到目前为止我的内容如下：

当前的PHP代码

if(isset($_POST["submit"])){
    $target_dir = "uploads/";
    $target_file = $target_dir . basename($_FILES["scans"]["name"]); //retain file after upload
    $uploadOk=1;
    move_uploaded_file($_FILES["scans"]["tmp_name"], $target_file);
    echo "Your file has been successfully uploaded.<br>";//let user know file has been received.
    $data=file_get_contents($target_file); //open uploaded file...
    for ($i=0; $i<$data; i++){
        list($k, $v) = explode(":", $data); //split list into key value pairs
    }
    $xml= new XMLWriter("<holding></holding>");//start new xml

Answer 1

你的基本循环看起来像这样：

$xml = new SimpleXMLElement('<xml/>');

foreach (exploe("\n", $data) as $row ) 
{

    $rowData = explode(":", $row);
    $xml->addChild(trim($rowData[0]), trim($rowData[1]));

}

echo "<pre>";
print_r( $xml->asXML() );
echo "</pre>";

这会在每个换行符处拆分文本文件，然后使用每行中第一个冒号左边的任何内容作为节点名称，并将每行中第一个冒号的任何内容作为节点值（或者更多）确切地说，无论第一个冒号和第二个冒号之间是否存在，如果它存在于同一行;您需要自己处理这些冒号。我在那里添加了一个修剪来杀死你的空白。

文本文件到XML？

1 个答案: